洛谷4014分配问题
题目链接:分配问题
这题比运输问题还裸啊
费用流模板题
#include<iostream>
#include<string>
#include<string.h>
#include<stdio.h>
#include<algorithm>
#include<math.h>
#include<vector>
#include<queue>
#include<map>
using namespace std;
#define rep(i,a,b) for (i=a;i<=b;i++)
typedef long long ll;
#define maxd 1e9+7
struct node{
int to,nxt,cost,flow;
}sq[100100];
int n,m,all=1,dis[100100],pre[100100],head[100100],s,t,maxf=0,minc=0,mp[110][110],flow[100100];
bool vis[100100];
void add(int u,int v,int f,int w)
{
all++;sq[all].to=v;sq[all].nxt=head[u];sq[all].cost=w;sq[all].flow=f;head[u]=all;
all++;sq[all].to=u;sq[all].nxt=head[v];sq[all].cost=-w;sq[all].flow=0;head[v]=all;
}
bool spfa()
{
queue<int> q;int i;
for (i=1;i<=t;i++) dis[i]=maxd;dis[s]=0;
memset(vis,0,sizeof(vis));
memset(flow,0,sizeof(flow));
vis[s]=1;q.push(s);flow[s]=maxd;
while (!q.empty())
{
int u=q.front();q.pop();vis[u]=0;
for (i=head[u];i;i=sq[i].nxt)
{
int v=sq[i].to;
if ((sq[i].flow) && (dis[v]>dis[u]+sq[i].cost))
{
dis[v]=sq[i].cost+dis[u];pre[v]=i;
flow[v]=min(flow[u],sq[i].flow);
if (!vis[v])
{
vis[v]=1;q.push(v);
}
}
}
}
return (dis[t]!=maxd);
}
void update()
{
int now=t;
maxf+=flow[t];
minc+=(flow[t]*dis[t]);
while (now!=s)
{
int tmp=pre[now];
sq[tmp].flow-=flow[t];
sq[tmp^1].flow+=flow[t];
now=sq[tmp^1].to;
}
}
int read()
{
int x=0,f=1;char ch=getchar();
while ((ch<'0') || (ch>'9')) {if (ch=='-') f=-1;ch=getchar();}
while ((ch>='0') && (ch<='9')) {x=x*10+(ch-'0');ch=getchar();}
return x*f;
}
void init()
{
n=read();s=n*2+1;t=n*2+2;
int i,j;
for (i=1;i<=n;i++)
{
for (j=1;j<=n;j++) mp[i][j]=read();
}
}
void init_max()
{
int i,j;all=1;
memset(head,0,sizeof(head));
for (i=1;i<=n;i++)
{
for (j=1;j<=n;j++)
{
add(i,j+n,1,-mp[i][j]);
}
add(s,i,1,0);
add(i+n,t,1,0);
}
}
void init_min()
{
int i,j;all=1;
memset(head,0,sizeof(head));
for (i=1;i<=n;i++)
{
for (j=1;j<=n;j++)
{
add(i,j+n,1,mp[i][j]);
}
add(s,i,1,0);
add(i+n,t,1,0);
}
}
void work(int fu)
{
maxf=0;minc=0;
while (spfa()) update();
printf("%d\n",minc*fu);
}
int main()
{
init();
init_min();
work(1);
init_max();
work(-1);
return 0;
}