递归构造树

@Data
@NoArgsConstructor
public class Foo {

    private Integer id;

    private Integer parentId;

    private List<Foo> children;

    public Foo(Integer id, Integer parentId) {
        this.id = id;
        this.parentId = parentId;
    }
}

 

public class FooTest {

    public static  Foo BuildTree(List<Foo> fooList){
        Foo root = new Foo();
        fooList.forEach(item ->{
            if(item.getParentId() == 0){
                root.setId(item.getId());
                root.setParentId(0);
                root.setChildren(getChild(item.getId(),fooList));
            }
        });
        return root;
    }
    private static List<Foo> getChild(Integer id, List<Foo> fooList) {
        List<Foo> child = Lists.newArrayList();
        fooList.forEach(item->{
            if(item.getParentId() == id){
                child.add(item);
            }
        });
        child.forEach(item ->{
            item.setChildren(getChild(item.getId(),fooList));
        });
        if(CollectionUtils.isEmpty(child)){
            return new ArrayList<Foo>();
        }
        return child;
    }

    public static void main(String[] args) {
        List<Foo> list = new ArrayList<>();
        list.add(new Foo(1,0));
        list.add(new Foo(2,1));
        list.add(new Foo(3,1));
        list.add(new Foo(4,1));
        list.add(new Foo(5,2));
        list.add(new Foo(6,3));
        Foo foo = BuildTree(list);
        System.out.println(foo);
    }
}

 

result:

Foo(id=1, parentId=0, children=[Foo(id=2, parentId=1, children=[Foo(id=5, parentId=2, children=[])]), Foo(id=3, parentId=1, children=[Foo(id=6, parentId=3, children=[])]), Foo(id=4, parentId=1, children=[])])

 

posted @ 2019-10-21 11:13  梦飞翔up  阅读(688)  评论(0编辑  收藏  举报