摘要: 1 写出一个函数,取到链表中倒数第二个节点。双链表:node* getSec(List mylist){ return mylist.m_tail->m_prev; //m_prev为链表前指针}单链表:node* getSec(List mylist){ node* rsec = mylist.m_head; node* rfirst = rsec->m_next; for(;rfirst != mylist.m_tail ; rsec = rsec->m_next) { rfirst = rsec->m_next;}return rsec;}2 找出数组中第二大的数 阅读全文
posted @ 2012-11-04 10:54 emmac 阅读(466) 评论(0) 推荐(0) 编辑