摘要: 题意:$\sum\limits_{i = 1}^n {\sum\limits_{j = 1}^m {lcm(i,j)} } $ 解题关键: $\sum\limits_{i = 1}^n {\sum\limits_{j = 1}^m {lcm(i,j)} } = \sum\limits_{i = 1} 阅读全文
posted @ 2017-10-03 19:11 Elpsywk 阅读(236) 评论(0) 推荐(0) 编辑