Java稀疏数组(内容整理)

package com.array;

public class ArrayDemo06 {          //稀疏数组
    public static void main(String[] args) {
        //1.创建一个11*11的二维数组 0：无棋子 1：黑棋 2：白棋
        int[][] array1=new int[11][11];
        array1[1][2]=1;
        array1[2][3]=2;

        System.out.println("输出原始数组：");
        for (int[] ints : array1) {
            for (int anInt : ints) {
                System.out.print(anInt+"\t");
            }
            System.out.println();
        }

        //转化为稀疏数组保存
        //获取有效值的个数
        int sum=0;

        for (int[] ints : array1) {
            for (int anInt : ints) {
                if(anInt!=0)sum++;
            }
        }

        System.out.println("有效值的个数为："+sum);   //输出2

        System.out.println("===============================");
        //2.创建一个稀疏数组
        int[][] array2=new int[sum+1][3];
        array2[0][0]=11;
        array2[0][1]=11;
        array2[0][2]=sum;

        //遍历二维数组，将非零的值存放在稀疏数组中
        int count=0;
        for (int i = 0; i < array1.length; i++) {
            for (int j = 0; j < array1[i].length; j++) {
                if(array1[i][j]!=0){
                    count++;
                    array2[count][0]=i;
                    array2[count][1]=j;
                    array2[count][2]=array1[i][j];

                }
            }
        }

        for (int[] ints : array2) {
            for (int anInt : ints) {
                System.out.print(anInt+"\t");
            }
            System.out.println();
        }

        System.out.println("===============================");
        //3.读取稀疏数组(还原)
        int[][] array3=new int[array2[0][0]][array2[0][1]];

        for (int i = 1; i < array2.length; i++) {
            array3[array2[i][0]][array2[i][1]]=array2[i][2];
        }

        System.out.println("输出还原的数组：");
        for (int[] ints : array3) {
            for (int anInt : ints) {
                System.out.print(anInt+"\t");
            }
            System.out.println();
        }

    }
}

 

输出结果：