ssh中的HibernateDaoSupport 实现分页

数据库为mysql5.0 表名为Author

struts2+hibernate3.0+spring3.0

首先是在自动生成的DAO里面加上如下代码


public List findAll(){
       
        String sql="FROM Author order by author_id";
        return getHibernateTemplate().find(sql);
    }

public List findAllByPage( final int pageNow, final int pageSize){

List list = (List) getHibernateTemplate().execute(
            new HibernateCallback() {
                int size=pageNow*pageSize-pageSize;
        public Object doInHibernate(Session session)
                throws HibernateException {
            Query q =session.createQuery("from Author order by author_id");
             q.setFirstResult(size);
             q.setMaxResults(pageSize);
             List cats = q.list();
            return cats;
        }
    });//内部类,返回一个List
     return list;
    }

然后就是在action里面定义




public int pageNow = 1 ; //初始化为1,默认从第一页开始显示
    public int pageSize =3 ; //每页显示5条记录 并生成get,set方法

public int getPageNow() {
        return pageNow;
    }

    public void setPageNow(int pageNow) {
        this.pageNow = pageNow;
    }

    public int getPageSize() {
        return pageSize;
    }

    public void setPageSize(int pageSize) {
        this.pageSize = pageSize;
    } 最后就是前台jsp的调用

<s:url id="url_pre" value="List.action">
         <s:param name="pageNow" value="pageNow-1"></s:param>
        
     </s:url>

     <s:url id="url_next" value="List.action">
         <s:param name="pageNow" value="pageNow+1"></s:param>
     </s:url>



<s:form action="List" theme="simple">
转到第<s:textfield name="pageNow"></s:textfield>页
<span><s:submit value=''GO'' name=''cndok''/></span>
</s:form>

<s:a href="%{url_pre}">上一页</s:a>



     <s:a href="%{url_next}">下一页</s:a>
posted @ 2008-10-31 18:45  Earl_86  阅读(600)  评论(0编辑  收藏  举报