POJ 2528 - Mayor's posters

其实就是区间用N个操作染色,问最后有多少种不同的颜色,注意由于范围较大需要map。

先拍了一个裸的,之所以称之为裸的是因为我觉得pushup是没必要存在的,先这样吧,改天再更新。

 1 #include <cstdio>
 2 #include <cstring>
 3 #include <algorithm>
 4 using namespace std;
 5 
 6 #define MAXV    32768
 7 
 8 int _v[MAXV << 1], *const v = &_v[-1];
 9 int _dirty[MAXV << 1], *const dirty = &_dirty[-1];
10 
11 #define recursive_def    int l, int r, int i
12 #define lsi            i<<1
13 #define rsi            i<<1 | 1
14 #define lsn            l, m, lsi
15 #define rsn            m+1, r, rsi
16 #define pushdown    if (dirty[i]) {\
17     dirty[lsi] = dirty[rsi] = dirty[i];    \
18     v[lsi] = v[rsi] = dirty[i];        \
19     dirty[i] = 0;}
20 #define pushup        (v[i] = v[lsi] != v[rsi]? -1 : v[lsi]);
21 
22 void build(recursive_def)
23 {
24     v[i] = dirty[i] = 0;
25     if (l != r) {
26         int m = l+r >> 1;
27         build(lsn), build(rsn);
28     }
29 }
30 
31 void update(int L, int R, int val, recursive_def)
32 {
33     if (L<=l && r<=R) v[i] = dirty[i] = val;
34     else {
35         pushdown
36         int m = l+r >> 1;
37         if (L<=m) update(L, R, val, lsn);
38         if (m < R) update(L, R, val, rsn);
39         pushup
40     }
41 }
42 
43 char mark[10005];
44 
45 int query(recursive_def){
46     if (v[i] >= 0)
47         if (!mark[v[i]]) {
48             mark[v[i]] = 1;
49             return 1;
50         } else return 0;
51     else {
52         int m = l+r >> 1;
53         return query(lsn) + query(rsn);
54     }
55 }
56 
57 int poster_l[10000], poster_r[10000];
58 int sorted[20000];
59 
60 int main(void)
61 {
62 //    freopen("hdu2528.txt", "r", stdin);
63     int C;
64     scanf("%d", &C);
65     while(C) {
66         int N;
67         scanf("%d", &N);
68         int L = 0;
69         for(int i=0; i<N; ++i) {
70             scanf("%d%d", &poster_l[i], &poster_r[i]);
71             sorted[L] = poster_l[i], sorted[L+1] = poster_r[i];
72             L += 2;
73         }
74         sort(sorted, sorted + L);
75         build(0, L-1, 1);
76         // map到 [0, L)上
77         for(int i=0; i<N; ++i) {
78             poster_l[i] = lower_bound(sorted, sorted + L, poster_l[i]) - sorted;
79             poster_r[i] = lower_bound(sorted, sorted + L, poster_r[i]) - sorted;
80             update(poster_l[i], poster_r[i], i+1, 0, L-1, 1);
81         }
82         memset(mark, 0, sizeof(mark));
83         mark[0] = 1;
84         printf("%d\n", query(0, L-1, 1));
85         --C;
86     }
87     return 0;
88 }

 

2528 Accepted 1036K 79MS G++ 1867B 2014-06-11 14:57:31
posted @ 2014-06-08 16:28  e0e1e  阅读(144)  评论(0编辑  收藏  举报