C#实现农历日历的方法
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本文实例讲述了C#实现农历日历的方法。分享给大家供大家参考。
具体实现方法如下:
//天干 private static string []TianGan = {"甲","乙","丙","丁","戊","己","庚","辛","壬","癸"}; //地支 private static string []DiZhi = {"子","丑","寅","卯","辰","巳","午","未","申","酉","戌","亥"}; //十二生肖 private static string []ShengXiao = {"鼠","牛","虎","兔","龙","蛇","马","羊","猴","鸡","狗","猪"}; //农历日期 private static string []DayName = {"*","初一","初二","初三","初四","初五","初六","初七","初八","初九","初十", "十一","十二","十三","十四","十五", "十六","十七","十八","十九","二十", "廿一","廿二","廿三","廿四","廿五", "廿六","廿七","廿八","廿九","三十"}; //农历月份 private static string []MonthName = {"*","正","二","三","四","五","六","七","八","九","十","十一","腊"}; //公历月计数天 private static int []MonthAdd = {0,31,59,90,120,151,181,212,243,273,304,334}; //农历数据 private static int []LunarData = {2635,333387,1701,1748,267701,694,2391,133423,1175,396438 ,3402,3749,331177,1453,694,201326,2350,465197,3221,3402 ,400202,2901,1386,267611,605,2349,137515,2709,464533,1738 ,2901,330421,1242,2651,199255,1323,529706,3733,1706,398762 ,2741,1206,267438,2647,1318,204070,3477,461653,1386,2413 ,330077,1197,2637,268877,3365,531109,2900,2922,398042,2395 ,1179,267415,2635,661067,1701,1748,398772,2742,2391,330031 ,1175,1611,200010,3749,527717,1452,2742,332397,2350,3222 ,268949,3402,3493,133973,1386,464219,605,2349,334123,2709 ,2890,267946,2773,592565,1210,2651,395863,1323,2707,265877}; /// <summary> /// 获取对应日期的农历 /// /// </summary> /// <param name="dtDay">公历日期</param> /// ///<returns></returns> public string GetLunarCalendar(DateTime dtDay) { string sYear = dtDay.Year.ToString(); string sMonth = dtDay.Month.ToString(); string sDay = dtDay.Day.ToString(); int year; int month; int day; try { year = int.Parse(sYear); month = int.Parse(sMonth); day = int.Parse(sDay); } catch { year = DateTime.Now.Year; month = DateTime.Now.Month; day = DateTime.Now.Day; } int nTheDate; int nIsEnd; int k, m, n, nBit, i; string calendar = string.Empty; //计算到初始时间1921年2月8日的天数:1921-2-8(正月初一) nTheDate = (year - 1921) * 365 + (year - 1921) / 4 + day + MonthAdd[month - 1] - 38; if ((year % 4 == 0) && (month > 2)) nTheDate += 1; //计算天干,地支,月,日 nIsEnd = 0; m = 0; k = 0; n = 0; while (nIsEnd != 1) { if (LunarData[m] < 4095) k = 11; else k = 12; n = k; while (n >= 0) { //获取LunarData[m]的第n个二进制位的值 nBit = LunarData[m]; for (i = 1; i < n + 1; i++) nBit = nBit / 2; nBit = nBit % 2; if (nTheDate <= (29 + nBit)) { nIsEnd = 1; break; } nTheDate = nTheDate - 29 - nBit; n = n - 1; } if (nIsEnd == 1) break; m = m + 1; } year = 1921 + m; month = k - n + 1; day = nTheDate; #region 格式化日期显示为三月廿四 if (k == 12) { if (month == LunarData[m] / 65536 + 1) month = 1 - month; else if (month > LunarData[m] / 65536 + 1) month = month - 1; } //生肖// calendar = ShengXiao[(year - 4) % 60 % 12].ToString() + "年 "; // // //天干// // calendar += TianGan[(year - 4) % 60 % 10].ToString(); // // //地支// // calendar += DiZhi[(year - 4) % 60 % 12].ToString() + " "; //// //农历月// if (month < 1) // calendar += "闰" + MonthName[-1 * month].ToString() + "月"; else calendar += MonthName[month].ToString() + "月"; //// //农历日// calendar += DayName[day].ToString() + "日";//// return calendar;//// #endregion }
希望本文所述对大家的C#程序设计有所帮助。