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摘要: Happy 2006 Time Limit: 3000MS Memory Limit: 65536K Description Two positive integers are said to be relatively prime to each other if the Great Common 阅读全文
posted @ 2017-01-30 17:42 mxzf0213 阅读(200) 评论(0) 推荐(0) 编辑
摘要: Co-prime Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Problem Description Given a number N, you are asked to count 阅读全文
posted @ 2017-01-30 17:33 mxzf0213 阅读(269) 评论(0) 推荐(0) 编辑
摘要: Nikita and stack time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output Nikita and stack time l 阅读全文
posted @ 2017-01-25 20:55 mxzf0213 阅读(438) 评论(0) 推荐(0) 编辑
摘要: Pavel and barbecue time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output Pavel and barbecue ti 阅读全文
posted @ 2017-01-25 20:49 mxzf0213 阅读(326) 评论(0) 推荐(0) 编辑
摘要: Travel Card time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output Travel Card time limit per t 阅读全文
posted @ 2017-01-25 20:45 mxzf0213 阅读(294) 评论(0) 推荐(0) 编辑
摘要: 2-SAT·hihoCoder音乐节 2-SAT·hihoCoder音乐节 时间限制:10000ms 单点时限:1000ms 内存限制:256MB 描述 hihoCoder音乐节由hihoCoder赞助商大力主办,邀请了众多嘉宾和知名乐队参与演出。 音乐会分为上午、下午两场进行,主办方指定了n首歌让 阅读全文
posted @ 2017-01-21 11:41 mxzf0213 阅读(207) 评论(0) 推荐(0) 编辑
摘要: Music in Car time limit per test 1 second memory limit per test 256 megabytes Music in Car time limit per test 1 second time limit per test memory lim 阅读全文
posted @ 2017-01-18 19:40 mxzf0213 阅读(318) 评论(0) 推荐(0) 编辑
摘要: Game with a Strip Time limit: 2.0 secondMemory limit: 64 MB There is a strip 1 × n with two sides. Each square of the strip (their total amount is 2n, 阅读全文
posted @ 2017-01-17 12:55 mxzf0213 阅读(321) 评论(0) 推荐(0) 编辑
摘要: Oleg and Little Ponies Time limit: 0.9 secondMemory limit: 64 MB Little boy Oleg loves the cartoon My Little Pony. How it cannot be loved, because the 阅读全文
posted @ 2017-01-17 11:59 mxzf0213 阅读(258) 评论(0) 推荐(0) 编辑
摘要: 分析:设方案数为ANS,C代表组合数; ANS=(C[K,I]*C[K-I,I][K-2*I,I]*...*C[K-(J-1)*I,I])/(J!); 也即: ANS=C[K,I*J]*(C[I*J,I]*C[I*J-I,I]*C[I*J-2*I,I]*...*C[I,I])/(J!); 又因为C[ 阅读全文
posted @ 2017-01-16 00:35 mxzf0213 阅读(310) 评论(0) 推荐(0) 编辑
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