摘要: Given an integer n, return the number of trailing zeroes in n!. Note: Your solution should be in logarithmic time complexity. 要求时间复杂度为log型 int trailingZeroes(int n) { int ret = 0; while(n) ... 阅读全文
posted @ 2015-10-27 09:19 dylqt 阅读(110) 评论(0) 推荐(0) 编辑