题意:给定一个长度小于40的序列,问你那是Fib数列的哪一项的前缀。
析:首先用大数把Fib数列的前100000-1项算出来,注意,一定不能是100000,要不然会WA的,然后每个数取前40位,不足40位的全取,然后插入到字典树上,
并用一个数组标记是哪一项,最后查询的时候,如果查不到就是无解,否则输出答案。
在我电脑上跑了10秒多,交上去才1秒多。
代码如下:
#pragma comment(linker, "/STACK:1024000000,1024000000") #include <cstdio> #include <string> #include <cstdlib> #include <cmath> #include <iostream> #include <cstring> #include <set> #include <queue> #include <algorithm> #include <vector> #include <map> #include <cctype> #include <cmath> #include <stack> #define debug() puts("++++"); #define gcd(a, b) __gcd(a, b) #define lson l,m,rt<<1 #define rson m+1,r,rt<<1|1 #define freopenr freopen("in.txt", "r", stdin) #define freopenw freopen("out.txt", "w", stdout) using namespace std; typedef long long LL; typedef unsigned long long ULL; typedef pair<int, int> P; const int INF = 0x3f3f3f3f; const double inf = 0x3f3f3f3f3f3f; const double PI = acos(-1.0); const double eps = 1e-5; const int maxn = 40000 + 10; const int mod = 1000000007; const int dr[] = {-1, 0, 1, 0}; const int dc[] = {0, 1, 0, -1}; const char *de[] = {"0000", "0001", "0010", "0011", "0100", "0101", "0110", "0111", "1000", "1001", "1010", "1011", "1100", "1101", "1110", "1111"}; int n, m; const int mon[] = {0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31}; const int monn[] = {0, 31, 29, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31}; inline bool is_in(int r, int c){ return r >= 0 && r < n && c >= 0 && c < m; } struct BigInteger{ static const int BASE = 100000000; static const int WIDTH = 8; vector<int> s; BigInteger(LL num = 0){ *this = num; } BigInteger operator = (LL num){ s.clear(); do{ s.push_back(num % BASE); num /= BASE; } while(num); return *this; } BigInteger operator = (const string &str){ s.clear(); int x, len = (str.length() - 1) / WIDTH + 1; for(int i = 0; i < len; ++i){ int end = str.length() - i * WIDTH; int start = max(0, end - WIDTH); sscanf(str.substr(start, end-start).c_str(), "%d", &x); s.push_back(x); } return *this; } friend istream &operator >> (istream &in, BigInteger &x){ string s; if(!(in >> s)) return in; x = s; return in; } string getNum(){ string ss; int t = s.back(); while(t) ss.push_back(t % 10 + '0'), t /= 10; reverse(ss.begin(), ss.end()); for(int i = s.size()-2; i >= 0; --i){ char buf[20]; sprintf(buf, "%08d", s[i]); int len = strlen(buf); for(int j = 0; j < len; ++j) ss.push_back(buf[j]); if(ss.size() >= 40) return ss; } return ss; } friend ostream &operator << (ostream &out, const BigInteger &x){ out << x.s.back(); for(int i = x.s.size()-2; i >= 0; --i){ char buf[20]; sprintf(buf, "%08d", x.s[i]); int len = strlen(buf); for(int j = 0; j < len; ++j) out << buf[j]; } return out; } BigInteger operator + (const BigInteger &b) const{ BigInteger c; c.s.clear(); for(int i = 0, g = 0; ; ++i){ if(!g && i >= s.size() && i >= b.s.size()) break; int x = g; if(i < s.size()) x += s[i]; if(i < b.s.size()) x += b.s[i]; c.s.push_back(x % BASE); g = x / BASE; } return c; } }; const int maxnode = 40 * 100000 + 10; const int sigam_size = 10; struct Tire{ int ch[maxnode][sigam_size]; int val[maxnode]; int sz; void init(){ sz = 1; memset(ch, 0, sizeof ch); memset(val, 0, sizeof val); } int idx(char c){ return c - '0'; } void Insert(const string &s, int v){ int u = 0; for(int i = 0; i < s.size(); ++i){ int c = idx(s[i]); if(!val[u]) val[u] = v; if(!ch[u][c]) ch[u][c] = sz++; u = ch[u][c]; } if(!val[u]) val[u] = v; } int query(const string &s){ int u = 0; for(int i = 0; i < s.size(); ++i){ int c = idx(s[i]); if(!ch[u][c]) return -1; u = ch[u][c]; } return val[u] - 1; } }; Tire fib; void init(){ fib.init(); BigInteger a = 1; BigInteger b = 1; BigInteger c = 1; fib.Insert(a.getNum(), 1); fib.Insert(a.getNum(), 2); for(int i = 2; i < 100000; ++i){ c = a + b; string s = c.getNum(); if(s.size() > 40) s = s.substr(0, 40); fib.Insert(s, i+1); a = b; b = c; } } int main(){ ios::sync_with_stdio(false); init(); int T; cin >> T; for(int kase = 1; kase <= T; ++kase){ string s; cin >> s; int ans = fib.query(s); cout << "Case #" << kase << ": " << ans << endl; } return 0; }