题意:给定n个立方体,让你重新涂尽量少的面,使得所有立方体都相同。
析:暴力求出每一种姿态,然后枚举每一种立方体的姿态,求出最少值。
代码如下:
#pragma comment(linker, "/STACK:1024000000,1024000000") #include <cstdio> #include <string> #include <cstdlib> #include <cmath> #include <iostream> #include <cstring> #include <set> #include <queue> #include <algorithm> #include <vector> #include <map> #include <cctype> #include <cmath> #include <stack> #define debug() puts("++++"); #define gcd(a, b) __gcd(a, b) #define lson l,m,rt<<1 #define rson m+1,r,rt<<1|1 #define freopenr freopen("in.txt", "r", stdin) #define freopenw freopen("out.txt", "w", stdout) using namespace std; typedef long long LL; typedef unsigned long long ULL; typedef pair<int, int> P; const int INF = 0x3f3f3f3f; const double inf = 0x3f3f3f3f3f3f; const double PI = acos(-1.0); const double eps = 1e-5; const int maxn = 20000 + 10; const int mod = 1e6 + 10; const int dr[] = {-1, 0, 1, 0}; const int dc[] = {0, 1, 0, -1}; const char *de[] = {"0000", "0001", "0010", "0011", "0100", "0101", "0110", "0111", "1000", "1001", "1010", "1011", "1100", "1101", "1110", "1111"}; int n, m; const int mon[] = {0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31}; const int monn[] = {0, 31, 29, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31}; inline bool is_in(int r, int c){ return r >= 0 && r < n && c >= 0 && c < m; } const int dice24[24][6] = { {2, 1, 5, 0, 4, 3}, {2, 0, 1, 4, 5, 3}, {2, 4, 0, 5, 1, 3}, {2, 5, 4, 1, 0, 3}, {4, 2, 5, 0, 3, 1}, {5, 2, 1, 4, 3, 0}, {1, 2, 0, 5, 3, 4}, {0, 2, 4, 1, 3, 5}, {0, 1, 2, 3, 4, 5}, {4, 0, 2, 3, 5, 1}, {5, 4, 2, 3, 1, 0}, {1, 5, 2, 3, 0, 4}, {5, 1, 3, 2, 4, 0}, {1, 0, 3, 2, 5, 4}, {0, 4, 3, 2, 1, 5}, {4, 5, 3, 2, 0, 1}, {1, 3, 5, 0, 2, 4}, {0, 3, 1, 4, 2, 5}, {4, 3, 0, 5, 2, 1}, {5, 3, 4, 1, 2, 0}, {3, 4, 5, 0, 1, 2}, {3, 5, 1, 4, 0, 2}, {3, 1, 0, 5, 4, 2}, {3, 0, 4, 1, 5, 2}, }; map<string, int> mp; int dice[10][10]; int ans; int r[10]; int getId(const string &s){ if(mp.count(s)) return mp[s]; return mp[s] = mp.size(); } int color[10][10]; void judge(){ for(int i = 0; i < n; ++i) for(int j = 0; j < 6; ++j) color[i][dice24[r[i]][j]] = dice[i][j]; int tot = 0; for(int i = 0; i < 6; ++i){ int cnt[30]; memset(cnt, 0, sizeof cnt); int mmax = 0; for(int j = 0; j < n; ++j) mmax = max(mmax, ++cnt[color[j][i]]); tot += n - mmax; } ans = min(ans, tot); } void dfs(int d){ if(d == n){ judge(); return ; } for(int i = 0; i < 24; ++i){ r[d] = i; dfs(d+1); } } int main(){ while(cin >> n && n){ mp.clear(); string s; for(int i = 0; i < n; ++i) for(int j = 0; j < 6; ++j){ cin >> s; dice[i][j] = getId(s); } ans = n * 6; r[0] = 0; dfs(1); cout << ans << endl; } return 0; }