题意:略。
析:裸的线段树。
代码如下:
#pragma comment(linker, "/STACK:1024000000,1024000000") #include <cstdio> #include <string> #include <cstdlib> #include <cmath> #include <iostream> #include <cstring> #include <set> #include <queue> #include <algorithm> #include <vector> #include <map> #include <cctype> #include <cmath> #include <stack> #define lson l,m,rt<<1 #define rson m+1,r,rt<<1|1 #define freopenr freopen("in.txt", "r", stdin) #define freopenw freopen("out.txt", "w", stdout) using namespace std; typedef long long LL; typedef pair<int, int> P; const int INF = 0x3f3f3f3f; const double inf = 0x3f3f3f3f3f3f; const double PI = acos(-1.0); const double eps = 1e-8; const int maxn = 200000 + 5; const int mod = 1e9 + 7; const int dr[] = {0, 1, 0, -1, -1, 1, 1, -1}; const int dc[] = {1, 0, -1, 0, 1, 1, -1, -1}; const char *de[] = {"0000", "0001", "0010", "0011", "0100", "0101", "0110", "0111", "1000", "1001", "1010", "1011", "1100", "1101", "1110", "1111"}; int n, m; const int mon[] = {0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31}; const int monn[] = {0, 31, 29, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31}; inline int Min(int a, int b){ return a < b ? a : b; } inline int Max(int a, int b){ return a > b ? a : b; } inline LL Min(LL a, LL b){ return a < b ? a : b; } inline LL Max(LL a, LL b){ return a > b ? a : b; } inline bool is_in(int r, int c){ return r >= 0 && r < n && c >= 0 && c < m; } int maxv[maxn<<2]; void pushup(int rt){ maxv[rt] = Max(maxv[rt<<1], maxv[rt<<1|1]); } void build(int l, int r, int rt){ if(l == r){ scanf("%d", &maxv[rt]); return ; } int m = (l + r) >> 1; build(lson); build(rson); pushup(rt); } void update(int x, int val, int l, int r, int rt){ if(l == r){ maxv[rt] = val; return ; } int m = (l + r) >> 1; if(x <= m) update(x, val, lson); if(x > m) update(x, val, rson); pushup(rt); } int query(int L, int R, int l, int r, int rt){ if(L <= l && r <= R) return maxv[rt]; int m = (l + r) >> 1; int ans = -INF; if(L <= m) ans = Max(ans, query(L, R, lson)); if(R > m) ans = Max(ans, query(L, R, rson)); return ans; } int main(){ while(scanf("%d %d", &n, &m) == 2){ build(1, n, 1); char s[5]; int x, y; while(m--){ scanf("%s", s); if(s[0] == 'Q'){ scanf("%d %d", &x, &y); printf("%d\n", query(x, y, 1, n, 1)); } else{ scanf("%d %d", &x, &y); update(x, y, 1, n, 1); } } } return 0; }