题意:给定 n 个人,和他们的数进行比较,从后面开始比,如果不够长,加middle接着比,直到没有,如果还相同比名字。
析:很水的题,就不用说了。
代码如下:
#pragma comment(linker, "/STACK:1024000000,1024000000") #include <cstdio> #include <string> #include <functional> #include <cstdlib> #include <cmath> #include <iostream> #include <cstring> #include <set> #include <queue> #include <algorithm> #include <vector> #include <deque> #include <map> #include <cctype> #include <stack> #include <sstream> using namespace std ; typedef long long LL; typedef pair<int, int> P; const int INF = 0x3f3f3f3f; const double inf = 0x3f3f3f3f3f3f; const double PI = acos(-1.0); const double eps = 1e-8; const int maxn = 1e3 + 5; const int mod = 1e9 + 7; const char *mark = "+-*"; const int dr[] = {-1, 0, 1, 0}; const int dc[] = {0, 1, 0, -1}; int n, m; inline bool is_in(int r, int c){ return r >= 0 && r < n && c >= 0 && c < m; } inline int Min(int a, int b){ return a < b ? a : b; } inline int Max(int a, int b){ return a > b ? a : b; } struct node{ string s; vector<int> v; }; node a[maxn]; string s; bool cmp(const node &lhs, const node &rhs){ int i = lhs.v.size()-1, j = rhs.v.size()-1; while(true){ if(i >= 0 && j >= 0){ if(lhs.v[i] != rhs.v[j]) return lhs.v[i] > rhs.v[j]; } else if(i >= 0){ if(lhs.v[i] != 1) return lhs.v[i] > 1; } else if(j >= 0){ if(rhs.v[j] != 1) return rhs.v[j] < 1; } --i, --j; if(i < 0 && j < 0) break; } return lhs.s < rhs.s; } int main(){ while(scanf("%d", &n) == 1){ for(int i = 0; i < n; ++i){ a[i].v.clear(); cin >> a[i].s; a[i].s.pop_back(); while(cin >> s && s[0] != 'c'){ if(s[0] == 'u') a[i].v.push_back(2); else if(s[0] == 'm') a[i].v.push_back(1); else a[i].v.push_back(0); } } sort(a, a+n, cmp); for(int i = 0; i < n; ++i) cout << a[i].s << endl; } return 0; }