题意:给定一个字符串,问你有多少种字母。
析:用set即可。
代码如下:
#pragma comment(linker, "/STACK:1024000000,1024000000") #include <cstdio> #include <string> #include <cstdlib> #include <cmath> #include <iostream> #include <cstring> #include <set> #include <queue> #include <algorithm> #include <vector> #include <map> #include <cctype> #include <stack> using namespace std; typedef long long LL; typedef pair<int, int> P; const int INF = 0x3f3f3f3f; const double inf = 0x3f3f3f3f3f3f; const LL LNF = 100000000000000000; const double PI = acos(-1.0); const double eps = 1e-8; const int maxn = 1e5 + 5; const int mod = 1e9 + 7; const char *mark = "+-*"; const int dr[] = {-1, 0, 1, 0}; const int dc[] = {0, 1, 0, -1}; int n, m; inline bool is_in(int r, int c){ return r >= 0 && r < n && c >= 0 && c < m; } inline LL Max(LL a, LL b){ return a < b ? b : a; } inline LL Min(LL a, LL b){ return a > b ? b : a; } inline int Max(int a, int b){ return a < b ? b : a; } inline int Min(int a, int b){ return a > b ? b : a; } set<char> sets; char s[maxn]; int main(){ int T; cin >> T; for(int kase = 1; kase <= T; ++kase){ sets.clear(); scanf("%s", s); n = strlen(s); for(int i = 0; i < n; ++i) sets.insert(s[i]); printf("Case #%d: %d\n", kase, sets.size()); } return 0; }