#include <stdio.h> #include <iostream> using namespace std; #define typec int // type of key val #define N 50005 int zabs(int x) { if (x < 0) return -x; else return x; } const int na = -1; struct node { typec key; int l, r, f, dist; } tr[N]; int ary[N]; int tree[N], size[N], cunt[N]; // 获得结点i的根 int iroot(int i) { if (i == na) return i; while (tr[i].f != na) i = tr[i].f; return i; } // 合并两棵左偏树, param: rx ry (two root) int merge(int rx, int ry) { if (rx == na) return ry; if (ry == na) return rx; if (tr[rx].key < tr[ry].key) swap(rx, ry); int r = merge(tr[rx].r, ry); tr[rx].r = r; tr[r].f = rx; if (tr[r].dist > tr[tr[rx].l].dist) swap(tr[rx].l, tr[rx].r); if (tr[rx].r == na) tr[rx].dist = 0; else tr[rx].dist = tr[tr[rx].r].dist + 1; return rx; // return new root } // 插入一个新节点 int ins(int i, typec key, int root) { tr[i].key = key; tr[i].l = tr[i].r = tr[i].f = na; tr[i].dist = 0; return root = merge(root, i); // return new root } // 删除某个结点 int del(int i) { if (i == na) return i; int x, y, l, r; l = tr[i].l; r = tr[i].r; y = tr[i].f; tr[i].l = tr[i].r = tr[i].f = na; tr[x = merge(l, r)].f = y; if (y != na && tr[y].l == i) tr[y].l = x; if (y != na && tr[y].r == i) tr[y].r = x; for ( ; y != na; x = y, y = tr[y].f) { if (tr[tr[y].l].dist < tr[tr[y].r].dist) swap(tr[y].l, tr[y].r); if (tr[tr[y].r].dist + 1 == tr[y].dist) break; tr[y].dist = tr[tr[y].r].dist + 1; } if (x != na) return iroot(x); // return new root else return iroot(y); } // 获取最小结点 node top(int root) { return tr[root]; } // 取得并删除最小结点 node pop(int &root) { node out = tr[root]; int l = tr[root].l, r = tr[root].r; tr[root].l = tr[root].r = tr[root].f = na; tr[l].f = tr[r].f = na; root = merge(l, r); return out; } // 增/减一个结点的键值 int add(int i, typec val) { if (i == na) return i; if (tr[i].l == na && tr[i].r == na && tr[i].f == na) { tr[i].key += val; return i; } typec key = tr[i].key + val; int rt = del(i); return ins(i, key, rt); } // 初始化数据 void init(int n) { for (int i = 0; i < n; i++) { scanf("%d", &ary[i]); tr[i].key = ary[i]; tr[i].l = tr[i].r = tr[i].f = na; tr[i].dist = 0; } } void solve(int n) { int m = -1; for (int i = 0; i < n; i++) { tree[++m] = i; size[m] = 1; cunt[m] = 1; while (m > 0 && top(tree[m]).key <= top(tree[m-1]).key) { tree[m-1] = merge(tree[m], tree[m-1]); size[m-1] += size[m]; cunt[m-1] += cunt[m]; m--; while (cunt[m] > (size[m] + 1) / 2) { pop(tree[m]); cunt[m]--; } } } int k = 0; long long res = 0; for (int i = 0; i <= m; i++) { int v = top(tree[i]).key; for (int j = 0; j < size[i]; j++) { res += zabs(ary[k++] - v); } } printf("%lld\n", res); } int main() { int n; while (scanf("%d", &n), n) { init(n); solve(n); } return 0; }
struct node { typec key; int l, r, f, dist; } tr[N];
1. // 获得结点i的根
2. int iroot(int i) {
3. if (i == na) return i;
4. while (tr[i].f != na) i = tr[i].f;
5. return i;
6. }
7. // 合并两棵左偏树, param: rx ry (two root)
8. int merge(int rx, int ry) {
9. if (rx == na) return ry;
10. if (ry == na) return rx;
11. if (tr[rx].key < tr[ry].key) swap(rx, ry);
12. int r = merge(tr[rx].r, ry);