摘要: inline void solve (int n) { for (int i = 1, top = 1; i <= n; i ++, top ++) { int cur = 0; for (int j = top; j <= n; j ++) if (mat[j][i]) { cur = j; br 阅读全文
posted @ 2022-10-05 11:14 duoluoluo 阅读(26) 评论(0) 推荐(0) 编辑
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