关于全局ID，雪花（snowflake）算法的说明

上次简单的说一下：http://www.cnblogs.com/dunitian/p/6041745.html#uid

C#版本的国外朋友已经封装了，大家可以去看看：https://github.com/ccollie/snowflake-net

强大的网友出来个简化版本：http://blog.csdn.net/***/article/details/*** （地址我就不贴了，对前辈需要最起码的尊敬）

一开始我用的是这个简化版本，后来发现有重复项。。。（demo：https://github.com/dunitian/TempCode/tree/master/2016-11-16/Twitter_Snowflake）

全局ID的激烈讨论：https://q.cnblogs.com/q/53552/

之后在外国大牛的基础上重写修改了部分内容（https://github.com/ccollie/snowflake-net），添加了一些注解等【支持Core】。现在是可以去Nuget直接下载使用的：Snowflake.Net

源码地址：https://github.com/dunitian/snowflake-net

测试用例：

测试代码：

using System;
using System.Collections.Generic;
using System.Threading;
using System.Threading.Tasks;
using Snowflake.Net;
 
namespace Snowflake.ZConsole
{
    class Program
    {
        private static int N = 2000000;
        private static HashSet<long> set = new HashSet<long>();
        private static IdWorker worker = new IdWorker(1, 1);
        private static int taskCount = 0;
 
        static void Main(string[] args)
        {
            Task.Run(() => GetID());
            Task.Run(() => GetID());
            Task.Run(() => GetID());
 
            Task.Run(() => Printf());
            Console.ReadKey();
        }
 
        private static void Printf()
        {
            while (taskCount != 3)
            {
                Console.WriteLine("...");
                Thread.Sleep(1000);
            }
            Console.WriteLine(set.Count == N * taskCount);
        }
 
        private static object o = new object();
        private static void GetID()
        {
            for (var i = 0; i < N; i++)
            {
                var id = worker.NextId();
 
                lock (o)
                {
                    if (set.Contains(id))
                    {
                        Console.WriteLine("发现重复项 : {0}", id);
                    }
                    else
                    {
                        set.Add(id);
                    }
                }
 
            }
            Console.WriteLine($"任务{++taskCount}完成");
        }
    }
}