摘要: uid,mid拼起来 关键词作为特征 SELECT FROM test1 left outer join test2 on test1.id = test2.id left outer join test3 on test1.id = test3.id label 0 阅读全文
posted @ 2015-10-13 09:57 dunfentiao 阅读(193) 评论(0) 推荐(0) 编辑