交叉表2

SELECT s.id,s.name,s.tid,t.typename,c.counts,c.time into #abc
FROM foods as s
INNER JOIN
foodtype as t
ON s.tid = t.id
INNER JOIN
foodcount as c
ON s.id=c.fid
exec p_qry #abc,typename,[time],counts,1,1

alter proc p_qry
@TableName sysname, --表名
@纵轴 sysname,  --交叉表最左面的列
@横轴 sysname,  --交叉表最上面的列
@表体内容 sysname, --交叉表的数数据字段
@是否加横向合计 bit,--为1时在交叉表横向最右边加横向合计
@是否家纵向合计 bit --为1时在交叉表纵向最下边加纵向合计
as
declare @s nvarchar(4000),@sql varchar(8000)

--判断横向字段是否大于纵向字段数目,如果是,则交换纵横字段
set @s='declare @a sysname
if(select count(distinct ['+@纵轴+'])from ['+@TableName+'])=1
 select @a=@纵轴,@纵轴=@横轴,@横轴=@a'
exec sp_executesql @s
 ,N'@纵轴 sysname out,@横轴 sysname out'
 ,@纵轴 out,@横轴 out

--生成交叉表处理语句
set @s='
set @s=''''
select @s=@s+'',[''+cast(['+@横轴+'] as varchar)+'']=sum(case ['+@横轴
 +'] when ''''''+cast(['+@横轴+'] as varchar)+'''''' then ['+@表体内容+'] else 0 end)''
from ['+@TableName+']
group by ['+@横轴+']'
exec sp_executesql @s
 ,N'@s varchar(8000) out'
 ,@sql out

--是否生成合计字段的处理
declare @sum1 varchar(200),@sum2 varchar(200),@sum3 varchar(200)
select @sum1=case @是否加横向合计
  when 1 then ',[合计]=sum(['+@表体内容+'])'
  else '' end
 ,@sum2=case @是否家纵向合计
  when 1 then '['+@纵轴+']=case grouping(['
   +@纵轴+']) when 1 then ''合计'' else cast(['
   +@纵轴+'] as varchar) end'
  else '['+@纵轴+']' end
 ,@sum3=case @是否家纵向合计
  when 1 then ' with rollup'
  else '' end

--生成交叉表
--print
exec('select '+@sum2+@sql+@sum1+'
from ['+@TableName+']
group by ['+@纵轴+']'+@sum3)
go