hdu 2053 Switch Game
Problem Description
There are many lamps in a line. All of them are off at first. A series of operations are carried out on these lamps. On the i-th operation, the lamps whose numbers are the multiple of i change the condition ( on to off and off to on ).
Input
Each test case contains only a number n ( 0< n<= 10^5) in a line.
Output
Output the condition of the n-th lamp after infinity operations ( 0 - off, 1 - on ).
Sample Input
1
5
Sample Output
1
0
Consider the second test case:
Hint
hintThe initial condition :0 0 0 0 0 …
After the first operation : 1 1 1 1 1 …
After the second operation : 1 0 1 0 1 …
After the third operation : 1 0 0 0 1 …
After the fourth operation : 1 0 0 1 1 …
After the fifth operation : 1 0 0 1 0 …
The later operations cannot change the condition of the fifth lamp any more. So the answer is 0.
这题是水题,找出n的约数的个数count,若为偶数则是0,若为奇数则为1;代码如下:
#include<iostream> #include<cmath> using namespace std; int main() { int n,i,count; while(scanf("%d",&n)!=EOF) { count=0; for(i=1;i<=sqrt(n);i++)//求n的约数的个数 { if(n%i==0) { count+=2; if(i==n/i) count--; } } if(count%2==0) printf("0\n"); else printf("1\n"); } return 0; }