Django源码分析之server

乍见

Django内置的server基本包括两部分:django.core.servers和django.core.handlers

相识

servers.basehttp是Django自身提供的一个用于开发测试的server模块,其中提供的WSGIServer、ServerHandler、WSGIRequestHandler其实都是属于WSGI server,django只不过是对python内置的WSGI模块simple_server做的一层包装。

handlers package包括base.py和wsgi.py两个模块。
base.py中只定义了一个BaseHandler类,它复杂一些基础的功能,比如加载中间件,处理异常,获取响应数据等

wsgi.py才是主角,其中最重要的就是WSGIHandler类,它继承了base.py中的BaseHandler,只添加了一个__call__方法,那为什么添加这个方法呢?

django.core.wsgi

import django
from django.core.handlers.wsgi import WSGIHandler


def get_wsgi_application():
    """
    The public interface to Django's WSGI support. Should return a WSGI
    callable.

    Allows us to avoid making django.core.handlers.WSGIHandler public API, in
    case the internal WSGI implementation changes or moves in the future.
    """
    django.setup()
    return WSGIHandler()

可见我们启动server时传入的application其实是WSGIHandler的一个实例,而根据WSGI规范,这个application必须要是callable,python中的callable包括函数、方法以及任何定义了__call__方法的对象

回到handlers.wsgi

class WSGIHandler(base.BaseHandler):
    initLock = Lock()
    request_class = WSGIRequest

    def __call__(self, environ, start_response):
        # Set up middleware if needed. We couldn't do this earlier, because
        # settings weren't available.
        if self._request_middleware is None:
            with self.initLock:
                try:
                    # Check that middleware is still uninitialized.
                    if self._request_middleware is None:
                        self.load_middleware()
                except:
                    # Unload whatever middleware we got
                    self._request_middleware = None
                    raise

        set_script_prefix(get_script_name(environ))
        signals.request_started.send(sender=self.__class__, environ=environ)
        try:
            request = self.request_class(environ)
        except UnicodeDecodeError:
            logger.warning('Bad Request (UnicodeDecodeError)',
                exc_info=sys.exc_info(),
                extra={
                    'status_code': 400,
                }
            )
            response = http.HttpResponseBadRequest()
        else:
            response = self.get_response(request)

        response._handler_class = self.__class__

        status = '%s %s' % (response.status_code, response.reason_phrase)
        response_headers = [(str(k), str(v)) for k, v in response.items()]
        for c in response.cookies.values():
            response_headers.append((str('Set-Cookie'), str(c.output(header=''))))
        start_response(force_str(status), response_headers)
        if getattr(response, 'file_to_stream', None) is not None and environ.get('wsgi.file_wrapper'):
            response = environ['wsgi.file_wrapper'](response.file_to_stream)
        return response

由于__call__是一个请求的入口,它需要调用BaseHandler中定义的方法去执行加载中间件等一系列操作和异常处理,除此之外,WSGIHandler还会处理cookie、触发signal等。

至于如何返回响应,具体可看handlers.base模块,大概就是找出请求的path,通过匹配路由,找到并执行用户定义的view方法,执行中间件处理方法,最后返回响应。当然,还有一系列的异常处理。

回想

这部分的内容需要对WSGi协议有个大致的了解,可以参考:http://xiaorui.cc/2016/04/16/%E6%89%93%E9%80%A0mvc%E6%A1%86%E6%9E%B6%E4%B9%8Bwsgi%E5%8D%8F%E8%AE%AE%E7%9A%84%E4%BC%98%E7%BC%BA%E7%82%B9%E5%8F%8A%E6%8E%A5%E5%8F%A3%E5%AE%9E%E7%8E%B0/

posted @ 2018-12-04 17:41  袋鼠云dtstack  阅读(140)  评论(0编辑  收藏  举报