P5055 【模板】可持久化文艺平衡树 可持久化fhqtreap
P5055 【模板】可持久化文艺平衡树
链接
思路
可持久化fhq-treap套一套就行了,pushdown和split都要可持久化,但merge不用可持久。以前以为很难一直没看,就是个板子。
错误
t[++num].sum=x;t[num].val=x;
t[++num].sum=t[num].val=x;
这两句话居然不一样。
我靠我靠我靠,调试了一下午。
代码
#include <bits/stdc++.h>
#define ll long long
using namespace std;
const int _=2e5+7;
ll read() {
ll x=0,f=1;char s=getchar();
for(;s>'9'||s<'0';s=getchar()) if(s=='-') f=-1;
for(;s>='0'&&s<='9';s=getchar()) x=x*10+s-'0';
return x*f;
}
namespace fhq_treap {
#define ls t[u].ch[0]
#define rs t[u].ch[1]
int num;
struct node {
int ch[2],siz,pri,lazy;
ll val,sum;
}t[_*80];
int make_node(ll x) {
t[++num].sum=x;t[num].val=x;
t[num].pri=rand(),t[num].siz=1;
return num;
}
void pushup(int u) {
t[u].siz=t[ls].siz+t[rs].siz+1;
t[u].sum=t[ls].sum+t[rs].sum+t[u].val;
}
int copy_node(int u) {t[++num]=t[u];return num;}
void pushdown(int u) {
if(t[u].lazy) {
if(ls) ls=copy_node(ls);
if(rs) rs=copy_node(rs);
if(ls) t[ls].lazy^=1;
if(rs) t[rs].lazy^=1;
swap(ls,rs);
t[u].lazy^=1;
}
}
int merge(int x,int y) {
if(!x||!y) return x+y;
pushdown(x),pushdown(y);
if(t[x].pri<t[y].pri) {
t[x].ch[1]=merge(t[x].ch[1],y);
pushup(x);return x;
} else {
t[y].ch[0]=merge(x,t[y].ch[0]);
pushup(y);return y;
}
}
void split(int u,int k,int &x,int &y) {
if(!u) x=y=0;
else {
pushdown(u);
u=copy_node(u);
if(t[ls].siz+1<=k)
x=u,split(rs,k-t[ls].siz-1,t[x].ch[1],y);
else
y=u,split(ls,k,x,t[y].ch[0]);
pushup(u);
}
}
}
using namespace fhq_treap;
int rt[_];
int main() {
srand(19260817);
int T=read();
ll lastans=0;
for(int i=1;i<=T;++i) {
int super_cool=read(),opt=read(),x,y,z;
if(opt==1) {
ll p=read()^lastans,v=read()^lastans;
split(rt[super_cool],p,x,y);
rt[i]=merge(merge(x,make_node(v)),y);
} else if(opt==2) {
ll p=read()^lastans;
split(rt[super_cool],p,x,z);
split(x,p-1,x,y);
rt[i]=merge(x,z);
} else if(opt==3) {
ll l=read()^lastans,r=read()^lastans;
split(rt[super_cool],r,x,z);
split(x,l-1,x,y);
t[y].lazy^=1;
rt[i]=merge(merge(x,y),z);
} else {
ll l=read()^lastans,r=read()^lastans;
split(rt[super_cool],r,x,z);
split(x,l-1,x,y);
printf("%lld\n",lastans=t[y].sum);
rt[i]=merge(merge(x,y),z);
}
}
return 0;
}