1065 A+B and C (64bit) (20 分)
Given three integers A, B and C in [−], you are supposed to tell whether A+B>C.
Input Specification:
The first line of the input gives the positive number of test cases, T (≤). Then T test cases follow, each consists of a single line containing three integers A, B and C, separated by single spaces.
Output Specification:
For each test case, output in one line Case #X: true
if A+B>C, or Case #X: false
otherwise, where X is the case number (starting from 1).
Sample Input:
3
1 2 3
2 3 4
9223372036854775807 -9223372036854775808 0
Sample Output:
Case #1: false
Case #2: true
Case #3: false
Thanks to Jiwen Lin for amending the test data.
思路:根据a,b,sum的正负判断是否溢出。注意:用cin输入会造成最后一个测试点过不去!!!,换成scanf输入
#include<bits/stdc++.h> using namespace std; const int maxn=1000010; int main(){ int n; long long a,b,c; long long sum=0; scanf("%lld",&n); for(int i=0;i<n;i++){ sum=0; scanf("%lld %lld %lld",&a,&b,&c); sum=a+b; if(a>0&&b>0&&sum<0){ printf("Case #%d: true\n",i+1); } else if(a<0&&b<0&&sum>=0){ printf("Case #%d: false\n",i+1); } else if(sum>c){ printf("Case #%d: true\n",i+1); } else{ printf("Case #%d: false\n",i+1); } } return 0; }