1132 Cut Integer (20 分)

Cutting an integer means to cut a K digits lone integer Z into two integers of (K/2) digits long integers A and B. For example, after cutting Z = 167334, we have A = 167 and B = 334. It is interesting to see that Z can be devided by the product of A and B, as 167334 / (167 × 334) = 3. Given an integer Z, you are supposed to test if it is such an integer.

Input Specification:

Each input file contains one test case. For each case, the first line gives a positive integer N (≤ 20). Then N lines follow, each gives an integer Z (10 ≤ Z <). It is guaranteed that the number of digits of Z is an even number.

Output Specification:

For each case, print a single line Yes if it is such a number, or No if not.

Sample Input:

3
167334
2333
12345678

 

Sample Output:

Yes
No
No

题解:
string的使用

#include<bits/stdc++.h>
using namespace std;
const int maxn=1010;
int main(){
    string z;
    string a,b;
    int n;
    cin>>n;
    while(n--){
        cin>>z;
        int len=z.length();
        a=z.substr(0,len/2);
        b=z.substr(len/2,len);
        int num1=0,num2=0,num=0;
        for(int i=0;i<z.length();i++){
            num=num*10+(z[i]-'0');
        }
        for(int i=0;i<a.length();i++){
            num1=num1*10+(a[i]-'0');
            num2=num2*10+(b[i]-'0');
        }
        int m;
        if(num1*num2==0){
            cout<<"No"<<endl;
            continue;
        }
        m=num/(num1*num2);
        if(m*num1*num2==num){
            cout<<"Yes"<<endl;
        }
        else{
            cout<<"No"<<endl;
        }
        }
    
    return 0;
}