一个关于字典的函数 

def cakes(recipe, available):
    d = [False for recipe_key in recipe.keys() if recipe_key not in available.keys()]
    if d:
       return 0
    else:
       return min([available[recipe_key]/recipe[recipe_key] for recipe_key in recipe.keys()])

 

def cakes(recipe, available):
  return min(available.get(k, 0)/recipe[k] for k in recipe)

 

 

posted @ 2017-10-23 23:11  不当咸鱼  阅读(172)  评论(0)  编辑  收藏  举报