面向对象程序设计第一次blog
一、前言
前三次的题目集中主要是关于Java语言的基本程序设计,前两次是熟悉Java语言语法,从最基础的命名变量、选择、循环、函数、字符及字符串到第三次作业的对象和类。题目集一题量较多,但是难度不高,考察的是Java基本语法,根据以前学过的C的知识能够完成,唯一注意的是数据的精度问题以及输入输出的格式问题。题目集二难度适中,考察Java中String的使用。而题目集三虽然题量不大,但是难度却比前两次高得多,初学表示非常艰难,且很多测试点根本想不出来。
总而言之,Java是本学期首次接触的语言,存在许多问题不足,还需要多多加强训练这样才能进步
二、设计分析
1.第二次作业(7-2 串口字符解析)
代码如下:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 | import java.util.Scanner; public class Main{ public static void main(String[] args) { // TODO Auto-generated method stub Scanner in = new Scanner(System.in); String s = in.nextLine(); int temp = 0 ; //记录十一位均为1 if (s.length()< 11 ) //小于最小长度 { System.out.println( "null data" ); return ; } for ( int i= 0 ;i< 11 ;i++) { if (s.charAt(i) == '1' ) temp++; } if (temp== 11 ) //输入数据全1,没有起始位 { System.out.println( "null data" ); return ; } if (s.matches( "^[1]*$" )) { System.out.println( "null data" ); return ; } int amount = 1 , num = 0 ,i = 0 ,a = 0 ; boolean flag = false ,index = false ; for (i= 0 ; i<s.length()- 10 ;i++) //判断无起始点且数据数不足 { if (s.charAt(i)== '0' ) //初始位置 { System.out.print(amount+ ":" ); amount++; if (s.charAt(i+ 10 )== '0' ) //奇偶校验位错误 { flag = false ; // System.out.println("parity check error"); } else { num = 0 ; flag = true ; for (a = i+ 1 ; a<i+ 9 ;a++) { if (s.charAt(a)== '1' ) { num++; } } if (num% 2 == 0 ) { if (s.charAt(i+ 9 )== '1' ) index = true ; else index = false ; } else { if (s.charAt(i+ 9 )== '0' ) index = true ; else index = false ; } } if (flag== true ) { if (index== true ) { for (a=i+ 1 ; a<i+ 9 ;a++) System.out.print(s.charAt(a)); //输出 System.out.print( "\n" ); } else { System.out.println( "parity check error" ); //奇偶校验错误 } } else { System.out.println( "validate error" ); //奇偶与结束符错误 } i = i+ 10 ; } } } } |
总结:本题对我来说难度不大,主要在于不同情况下数据读取判断,使用多组for循环来进行读取判断和输出,导致圈复杂度很高
2.第三次作业(7-1 点线形系列1-计算两点之间的距离)
代码如下:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 | import java.util.Scanner; public class Main { public static void main(String[] args) { // TODO Auto-generated method stub Scanner in = new Scanner(System.in); String s = in.nextLine(); int m = 0 ; //遇到逗号 int n = 0 ; //遇到空格 int flag = 1 ; //输入合法性检验 for ( int i= 0 ;i<s.length();i++) { if (s.charAt(i)== ',' ) { m++; } if (s.charAt(i)== ' ' ) { n++; } if (s.charAt(i)== '+' ||s.charAt(i)== '-' ||s.charAt(i)== '.' ) { if (s.charAt(i+ 1 )>= '0' &&s.charAt(i+ 1 )<= '9' ) { //合法输入 continue ; } else { flag = 0 ; break ; } } } if (m-n!= 1 ) { flag = 0 ; } if (flag == 1 ) { if (m!= 2 ) { //坐标点数量超过两个 System.out.println( "wrong number of points" ); } else { String []a = new String[ 4 ]; //存放数据 for ( int i = 0 ;i< 4 ;i++) { a[i] = new String(); } int p = 0 ; for ( int i = 0 ;i<s.length();i++) { //存放 ,或空格 if (s.charAt(i)!= ' ' &&s.charAt(i)!= ',' ) { a[p] = a[p] + s.substring(i,i+ 1 ); } else { p++; } } int index = 1 ; for ( int i = 0 ;i< 4 ;i++) { //判断每个数字前 + - 是否只有一个 if (a[i].charAt( 0 )== '+' ||a[i].charAt( 0 )== '-' ) { if (a[i].charAt( 1 )== '0' &&a[i].charAt( 2 )!= '.' ) { index = 0 ; } } else { if (a[i].length()>= 2 ) { if (a[i].charAt( 0 )== '0' &&a[i].charAt( 1 )!= '.' ) { index = 0 ; } } } if (index == 0 ) { break ; } } if (index == 0 ) { System.out.println( "Wrong Format" ); } else { double x1,x2,y1,y2; x1 = Double.parseDouble(a[ 0 ]); y1 = Double.parseDouble(a[ 1 ]); x2 = Double.parseDouble(a[ 2 ]); y2 = Double.parseDouble(a[ 3 ]); double distance = Math.sqrt((x1-x2)*(x1-x2)+(y1-y2)*(y1-y2)); //计算 System.out.println(distance); } } } else { System.out.println( "Wrong Format" ); } } } |
总结:这道题的题目要求很简单,就是计算两点间距离,但是它对数据输入输出的格式有很高的要求,如果输入数据不符合坐标形式,程序就要报错提醒,并且也需要格外注意坐标点数量。由于输入数据中包含空格以及逗号,我们输入时应选择字符串输入,并要对数据进行校验。在做好对输入数据的校验后,我用数组进行存放数据,最后通过距离公式来进行计算。此外,本题可以设计一个点类来完成。
3.题目三(7-2 点线形系列2-线的计算)
代码如下:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 119 120 121 122 123 124 125 126 127 128 129 130 131 132 133 134 135 136 137 138 139 140 141 142 143 144 145 146 147 148 149 150 151 152 153 154 155 156 157 158 159 160 161 162 163 164 165 166 167 168 169 170 171 172 173 174 175 176 177 178 179 180 181 182 183 184 185 186 187 188 189 190 191 192 193 194 195 196 197 198 199 200 201 202 203 204 205 206 207 208 209 210 211 212 213 214 215 216 217 218 219 220 221 222 223 224 225 226 227 228 229 230 231 232 233 234 235 236 237 238 239 240 241 242 243 244 245 246 247 248 249 250 251 252 253 254 255 256 257 258 259 260 261 262 263 264 265 266 267 268 269 270 271 272 273 274 275 276 277 278 279 280 281 282 283 284 285 286 287 288 289 290 291 292 293 294 295 296 297 298 299 300 301 302 303 304 305 306 307 308 309 310 311 312 313 314 315 316 317 318 319 320 321 322 323 324 325 326 327 328 329 330 331 332 333 334 335 | import java.util.Scanner; public class Main { public static void main(String[] args) { // TODO Auto-generated method stub Scanner in = new Scanner(System.in); String s = in.nextLine(); String []arry = new String[ 20 ]; String [] str= s.split( ":" ); int n = str.length; int j = 0 ,k = 0 ; //数组下标 int index = 2 ; //坐标从第三个字符开始 int flag = 0 ,temp = 0 ; if (n== 2 ){ if (s.charAt( 0 )<= 0 &&s.charAt( 0 )>= 6 ) { System.out.println( "Wrong Format" ); return ; } if (s.charAt( 1 )!= ':' ) { System.out.println( "Wrong Format" ); return ; } for ( int i= 2 ;i<s.length();i++) { if (s.charAt(i)== ' ' ) { temp++; } if (s.charAt(i)== ',' ){ k++; } } for ( int i= 2 ;i<s.length();i++) { //记录点 if (s.charAt(i)== ',' ||s.charAt(i)== ' ' ) { arry[j] = s.substring(index,i); index = i+ 1 ; j++; flag = i; } } if (k == 2 ) { //两个点 arry[ 3 ] = s.substring(flag+ 1 ,s.length()); double x1 = Double.parseDouble(arry[ 0 ]); double y1 = Double.parseDouble(arry[ 1 ]); double x2 = Double.parseDouble(arry[ 2 ]); double y2 = Double.parseDouble(arry[ 3 ]); for ( int i= 0 ;i<s.length();i++) { if (s.charAt(i)== '1' &&s.charAt(i+ 1 )== ':' ) { Point point = new Point(x1,y1,x2,y2); point.slope(); } if (temp == 2 ) { System.out.println( "wrong number of points" ); } } } else if (k == 3 ) { //三个点 arry[ 5 ] = s.substring(flag+ 1 ,s.length()); double x1 = Double.parseDouble(arry[ 0 ]); double y1 = Double.parseDouble(arry[ 1 ]); double x2 = Double.parseDouble(arry[ 2 ]); double y2 = Double.parseDouble(arry[ 3 ]); double x3 = Double.parseDouble(arry[ 4 ]); double y3 = Double.parseDouble(arry[ 5 ]); if (s.charAt( 0 )== '2' ) { //选项2 Point point = new Point(x1,y1,x2,y2,x3,y3); point.threepointdistance(); } if (s.charAt( 0 )== '3' ) { //选项3 Point point = new Point(x1,y1,x2,y2,x3,y3); point.threepointline(); } if (temp == 3 ){ System.out.println( "wrong number of points" ); } } else if (k == 4 ) { //四个点 arry[ 7 ] = s.substring(flag+ 1 ,s.length()); double x1 = Double.parseDouble(arry[ 0 ]); double y1 = Double.parseDouble(arry[ 1 ]); double x2 = Double.parseDouble(arry[ 2 ]); double y2 = Double.parseDouble(arry[ 3 ]); double x3 = Double.parseDouble(arry[ 4 ]); double y3 = Double.parseDouble(arry[ 5 ]); double x4 = Double.parseDouble(arry[ 6 ]); double y4 = Double.parseDouble(arry[ 7 ]); if (s.charAt( 0 )== '4' ) { Point point = new Point(x1,y1,x2,y2,x3,y3,x4,y4); point.fourpointsparalle(); } if (s.charAt( 0 )== '5' ) { Point point = new Point(x1,y1,x2,y2,x3,y3,x4,y4); point.jiaodian(); } if (temp == 4 ) { System.out.println( "wrong number of points" ); } } else if (k> 4 ) { //输入点数量不符合要求 System.out.println( "wrong number of points" ); } } else { System.out.println( "Wrong Format" ); } } } class Point { private double x1,y1,x2,y2,x3,y3,x4,y4; public Point() { super (); } public Point( double x1, double y1, double x2, double y2) { super (); this .x1 = x1; this .y1 = y1; this .x2 = x2; this .y2 = y2; } public Point( double x1, double y1, double x2, double y2, double x3, double y3) { super (); this .x1 = x1; this .y1 = y1; this .x2 = x2; this .y2 = y2; this .x3 = x3; this .y3 = y3; } public Point( double x1, double y1, double x2, double y2, double x3, double y3, double x4, double y4) { super (); this .x1 = x1; this .y1 = y1; this .x2 = x2; this .y2 = y2; this .x3 = x3; this .y3 = y3; this .x4 = x4; this .y4 = y4; } public double getx1() { return x1; } public void setx1( double x1) { this .x1 = x1; } public double gety1() { return y1; } public void sety1( double y1) { this .y1 = y1; } public double getx2() { return x2; } public void setx2( double x2) { this .x2 = x2; } public double gety2() { return y2; } public void sety2( double y2) { this .y2 = y2; } public double getx3() { return x3; } public void setx3( double x3) { this .x3 = x3; } public double gety3() { return y3; } public void sety3( double y3) { this .y3 = y3; } public double getx4() { return x4; } public void setx4( double x4) { this .x4 = x4; } public double gety4() { return y4; } public void sety4( double y4) { this .y4 = y4; } public boolean chonghe( double x1, double y1, double x2, double y2) { //判断两点是否重合 if (x1==x2&&y1==y2) { return true ; } else { return false ; } } public void slope() { //斜率 double k = 0 ; k = (y1-y2)/(x1-x2); if (chonghe(x1,y1,x2,y2)) { System.out.println( "points coincide" ); //两点重合 } else { if (x1==x2) { //分母为0 线条垂直于x轴 System.out.println( "Slope does not exist" ); } else { System.out.println(k); } } } public void threepointdistance() { //第一个点与另外两条点所成线距离 double distance = Math.abs((y2-y3)*x1+(x3-x2)*y1+x2*y3-y2*x3)/Math.sqrt((y2-y3)*(y2-y3)+(x2-x3)*(x2-x3)); if (!chonghe(x2,y2,x3,y3)) { System.out.println(distance); } else { System.out.println( "points coincide" ); } } public void threepointline() { double k1,k2; k1 = (y1-y2)/(x1-x2); k2 = (y1-y3)/(x1-x3); if (!chonghe(x1,y1,x2,y2)&&!chonghe(x1,y1,x3,y3)) { if (x1==x2&&x1==x3) { System.out.println( "true" ); } else { if (k1==k2) { System.out.println( "true" ); } else { System.out.println( "false" ); } } } else { System.out.println( "points coincide" ); } } public void fourpointsparalle() { if (chonghe(x1,y1,x2,y2)||chonghe(x3,y3,x4,y4)) { System.out.println( "points coincide" ); } else { if ((x1-x2)*(y3-y4)==(y1-y2)*(x3-x4)) { System.out.println( "true" ); } else { System.out.println( "false" ); } } } public double max( double x1, double x2) { if (x1>x2) { return x1; } else { return x2; } } public double min( double x1, double x2) { if (x1>x2) { return x2; } else { return x1; } } public boolean isinline( double x, double y) { //判断交点是否在线段上 double max1 = max(x1,x2); double max2 = max(x3,x4); double min1 = min(x1,x2); double min2 = min(x3,x4); if ((x>min1||x>min2)&&(x<max1||x<max2)) { return true ; } else { return false ; } } public void jiaodian() { double k1,k2; double x,y; x = (y3*x2*x4-x3*y4*x2-y3*x1*x4+y4*x1*x3-y1*x4*x2+y2*x4*x1+y1*x2*x3-y2*x1*x3)/(x4*y2-x4*y1-x3*y2+x3*y1-x2*y4+x2*y3+x1*y4-x1*y3); y = (-y2*x4*y3+y2*x3*y4+y3*x4*y1-y4*x3*y1+y4*x2*y1-y1*x2*y3-y4*x1*y2+y2*x1*y3)/(y4*x2-y4*x1-y3*x2+x1*y3-y2*x4+y2*x3+y1*x4-y1*x3); k1 = (y2-y1)/(x2-x1); k2 = (y4-y3)/(x4-x3); if (chonghe(x1,y1,x2,y2)||chonghe(x3,y3,x4,y4)) { System.out.println( "points coincide" ); } else { if (k1==k2||(x1==x2&&x3==x4)) { System.out.println( "is parallel lines,have no intersection point" ); } else { System.out.println(x+ "," +y+ " " +isinline(x,y)); } } } } |
总结:这道题属于7-1的进阶版,由单纯点的问题转为线的问题,出现四五个点的情况,题目中需求也变得极为多,测试点也极为***钻。这道题我设计点类来对这些需求进行计算,在此之前,还是需要对输入数据进行校验以及处理,要将输入字符拆分存放入数组,采用if判断语句来进行不同要求间算法的求解。但由于我对输入格式的判断存在问题,数据格式的输入测试点过不去,本题没有拿到满分。
SourceMonitor分析图:
4.作业3(7-3 点线形系列3-三角形的计算)
代码如下:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 119 120 121 122 123 124 125 126 127 128 129 130 131 132 133 134 135 136 137 138 139 140 141 142 143 144 145 146 147 148 149 150 151 152 153 154 155 156 157 158 159 160 161 162 163 164 165 166 167 168 169 170 171 172 173 174 175 176 177 178 179 180 181 182 183 184 185 186 187 188 189 190 191 192 193 194 195 196 197 198 199 200 201 202 203 204 205 206 207 208 209 210 211 212 213 214 215 216 217 218 219 220 221 222 223 224 225 226 227 228 229 230 231 232 233 234 235 236 237 238 239 240 241 242 243 244 245 246 247 248 249 250 251 252 253 254 255 256 257 258 259 260 261 262 263 264 265 266 267 268 269 270 271 272 273 274 275 276 277 278 279 280 281 282 283 284 285 286 287 288 289 290 291 292 293 294 295 296 297 298 299 300 301 302 303 304 305 306 307 308 309 310 311 312 313 314 315 316 317 318 319 320 321 322 323 324 325 326 327 328 329 330 331 332 333 334 335 336 337 338 339 340 341 342 343 344 345 346 347 348 349 350 351 352 353 354 355 356 357 358 359 360 361 362 363 364 365 366 367 368 369 370 371 372 373 374 375 376 377 378 379 380 381 382 383 384 385 386 387 388 389 390 391 392 393 394 395 396 397 398 399 400 401 402 403 404 405 406 407 408 409 410 411 412 413 414 415 416 417 418 419 420 421 422 423 424 425 426 427 428 429 430 431 432 433 434 435 436 437 438 439 440 441 442 443 444 445 446 447 448 449 450 451 452 453 454 455 456 457 458 459 460 461 462 463 464 465 466 467 468 469 470 471 472 473 474 475 476 477 478 479 480 481 482 483 484 485 486 487 488 489 490 491 492 493 494 495 496 497 498 499 500 501 502 503 504 505 506 507 508 509 510 511 512 513 514 515 516 517 518 519 520 521 522 523 524 525 526 527 528 529 530 531 532 533 534 535 536 537 538 539 540 541 542 543 544 545 546 547 548 549 550 551 552 553 554 555 556 557 558 559 560 561 562 563 564 565 566 567 568 569 570 571 572 573 574 575 576 577 578 579 580 581 582 583 584 585 586 587 588 589 590 591 592 593 594 595 596 597 598 599 600 601 602 603 604 605 606 607 608 609 610 611 612 613 614 615 616 617 618 619 620 621 622 623 624 625 626 627 628 629 630 631 632 633 634 635 636 637 638 639 640 641 642 643 644 645 646 647 648 649 650 651 652 653 654 655 656 657 658 659 660 661 662 663 664 665 666 667 668 669 670 671 672 673 674 675 676 677 678 679 680 681 682 683 684 685 686 687 688 689 690 691 692 693 694 695 696 697 698 699 700 701 702 703 704 705 706 707 708 709 710 711 | // package 作业第三题; import java.util.Scanner; import java.text.DecimalFormat; public class Main { public static void main(String[] args) { // TODO Auto-generated method stub Scanner in = new Scanner(System.in); String s = in.nextLine(); String []arry = new String[ 20 ]; int j = 0 ,k = 0 ; //数组下标 int index = 2 ; //坐标从第三个字符开始 int flag = 0 ,temp = 0 ; boolean a = false ; if (s.charAt( 0 )<= 0 &&s.charAt( 0 )>= 6 ) { System.out.print( "Wrong Format" ); return ; } for ( int i= 0 ;i<s.length();i++) { if (s.charAt(i)== ' ' ) { a = true ; } } if (s.charAt( 1 )!= ':' ||a== false ) { System.out.print( "Wrong Format" ); return ; } if (!s.matches( "^[1-5][:](([+-]?(0|(0\\.\\d+)|[1-9][0-9]*(\\.\\d+)?))[,]([+-]?(0|(0\\.\\d+)|[1-9][0-9]*(\\.\\d+)?))\\s?)+$" )){ System.out.println( "Wrong Format" ); return ; } for ( int i= 2 ;i<s.length();i++) { if (s.charAt(i)== ' ' ) { temp++; } if (s.charAt(i)== ',' ) { k++; } } for ( int i= 2 ;i<s.length();i++) { //记录点 if (s.charAt(i)== ',' ||s.charAt(i)== ' ' ) { arry[j] = s.substring(index,i); index = i+ 1 ; j++; flag = i; } } if (k == 3 ) { //三个点 arry[ 5 ] = s.substring(flag+ 1 ,s.length()); double x1 = Double.parseDouble(arry[ 0 ]); double y1 = Double.parseDouble(arry[ 1 ]); double x2 = Double.parseDouble(arry[ 2 ]); double y2 = Double.parseDouble(arry[ 3 ]); double x3 = Double.parseDouble(arry[ 4 ]); double y3 = Double.parseDouble(arry[ 5 ]); if (s.charAt( 0 )== '1' ) { //选项1 Point point = new Point(x1,y1,x2,y2,x3,y3); point.threetriangle(); } if (s.charAt( 0 )== '2' ) { //选项2 Point point = new Point(x1,y1,x2,y2,x3,y3); point.threepointscalculate(); } if (s.charAt( 0 )== '3' ) { //选项3 Point point = new Point(x1,y1,x2,y2,x3,y3); point.panduantriangle(); } } else if (k == 4 ) { //四个点 arry[ 7 ] = s.substring(flag+ 1 ,s.length()); double x1 = Double.parseDouble(arry[ 0 ]); double y1 = Double.parseDouble(arry[ 1 ]); double x2 = Double.parseDouble(arry[ 2 ]); double y2 = Double.parseDouble(arry[ 3 ]); double x3 = Double.parseDouble(arry[ 4 ]); double y3 = Double.parseDouble(arry[ 5 ]); double x4 = Double.parseDouble(arry[ 6 ]); double y4 = Double.parseDouble(arry[ 7 ]); if (s.charAt( 0 )== '5' ) { //选项五 Point point = new Point(x1,y1,x2,y2,x3,y3,x4,y4); point. } } else if (k == 5 ) { //五个点 arry[ 9 ] = s.substring(flag+ 1 ,s.length()); double x1 = Double.parseDouble(arry[ 0 ]); double y1 = Double.parseDouble(arry[ 1 ]); double x2 = Double.parseDouble(arry[ 2 ]); double y2 = Double.parseDouble(arry[ 3 ]); double x3 = Double.parseDouble(arry[ 4 ]); double y3 = Double.parseDouble(arry[ 5 ]); double x4 = Double.parseDouble(arry[ 6 ]); double y4 = Double.parseDouble(arry[ 7 ]); double x5 = Double.parseDouble(arry[ 8 ]); double y5 = Double.parseDouble(arry[ 9 ]); if (s.charAt( 0 )== '4' ) { //选项四 Point point = new Point(x1,y1,x2,y2,x3,y3,x4,y4,x5,y5); point.fivepointstriangle(); } } else if (k> 5 ) { System.out.println( "wrong number of points" ); } } } // package 作业第三题; // import java.text.DecimalFormat; class Point { private double x1,y1,x2,y2,x3,y3,x4,y4,x5,y5; private double x,y; public Point() { super (); } public Point( double x1, double y1, double x2, double y2) { super (); this .x1 = x1; this .y1 = y1; this .x2 = x2; this .y2 = y2; } public Point( double x1, double y1, double x2, double y2, double x3, double y3) { super (); this .x1 = x1; this .y1 = y1; this .x2 = x2; this .y2 = y2; this .x3 = x3; this .y3 = y3; } public Point( double x1, double y1, double x2, double y2, double x3, double y3, double x4, double y4) { super (); this .x1 = x1; this .y1 = y1; this .x2 = x2; this .y2 = y2; this .x3 = x3; this .y3 = y3; this .x4 = x4; this .y4 = y4; } public Point( double x1, double y1, double x2, double y2, double x3, double y3, double x4, double y4, double x5, double y5) { super (); this .x1 = x1; this .y1 = y1; this .x2 = x2; this .y2 = y2; this .x3 = x3; this .y3 = y3; this .x4 = x4; this .y4 = y4; this .x5 = x5; this .y5 = y5; } public double getx1() { return x1; } public void setx1( double x1) { this .x1 = x1; } public double gety1() { return y1; } public void sety1( double y1) { this .y1 = y1; } public double getx2() { return x2; } public void setx2( double x2) { this .x2 = x2; } public double gety2() { return y2; } public void sety2( double y2) { this .y2 = y2; } public double getx3() { return x3; } public void setx3( double x3) { this .x3 = x3; } public double gety3() { return y3; } public void sety3( double y3) { this .y3 = y3; } public double getx4() { return x4; } public void setx4( double x4) { this .x4 = x4; } public double gety4() { return y4; } public void sety4( double y4) { this .y4 = y4; } public double getx5() { return x5; } public void setx5( double x5) { this .x5 = x5; } public double gety5() { return y5; } public void sety5( double y5) { this .y5 = y5; } public boolean chonghe( double x1, double y1, double x2, double y2) { //判断两点是否重合 if (x1==x2&&y1==y2) { return true ; } else { return false ; } } public boolean triangle( double x1, double y1, double x2, double y2, double x3, double y3) { //判断是否为三角形 double a,b,c; a = Math.sqrt((x1-x2)*(x1-x2)+(y1-y2)*(y1-y2)); b = Math.sqrt((x1-x3)*(x1-x3)+(y1-y3)*(y1-y3)); c = Math.sqrt((x3-x2)*(x3-x2)+(y3-y2)*(y3-y2)); if (a+b>c&&a+c>b&&b+c>a) { return true ; } else { return false ; } } public void threetriangle() { double a,b,c; a = Math.sqrt((x1-x2)*(x1-x2)+(y1-y2)*(y1-y2)); b = Math.sqrt((x1-x3)*(x1-x3)+(y1-y3)*(y1-y3)); c = Math.sqrt((x3-x2)*(x3-x2)+(y3-y2)*(y3-y2)); if (!triangle(x1,y1,x2,y2,x3,y3)) { System.out.println( "data error" ); } else { if (a==b||a==c||b==c) { System.out.print( "true" ); } else { System.out.print( "false" ); } System.out.print( " " ); if (a==b&&a==c&&b==c) { System.out.print( "true" ); } else { System.out.print( "false" ); } } } public void threepointscalculate() { double a,b,c; a = Math.sqrt((x1-x2)*(x1-x2)+(y1-y2)*(y1-y2)); b = Math.sqrt((x1-x3)*(x1-x3)+(y1-y3)*(y1-y3)); c = Math.sqrt((x3-x2)*(x3-x2)+(y3-y2)*(y3-y2)); double C = a+b+c; //周长 double S = Math.sqrt((C/ 2 )*(C/ 2 -a)*(C/ 2 -b)*(C/ 2 -c)); //面积 double X = (x1+x2+x3)/ 3 ; double Y = (y1+y2+y3)/ 3 ; if (!triangle(x1,y1,x2,y2,x3,y3)) { System.out.println( "data error" ); } else { // System.out.println(C+" "+S+" "+X+","+Y); // System.out.printf("%.6f %.6f %.6f %.6f",C,S,X,Y); // System.out.print(C); // System.out.print(" "); // System.out.print(S); // System.out.print(" "); // System.out.print(X); // System.out.print(","); // System.out.print(Y); System.out.printf( new DecimalFormat( "0.0#####" ).format(C)); System.out.print( " " ); System.out.printf( new DecimalFormat( "0.0#####" ).format(S)); System.out.print( " " ); System.out.printf( new DecimalFormat( "0.0#####" ).format(X)); System.out.print( "," ); System.out.printf( new DecimalFormat( "0.0#####" ).format(Y)); } } public void panduantriangle() { double a,b,c,A,B,C; a = Math.sqrt((x1-x2)*(x1-x2)+(y1-y2)*(y1-y2)); b = Math.sqrt((x1-x3)*(x1-x3)+(y1-y3)*(y1-y3)); c = Math.sqrt((x3-x2)*(x3-x2)+(y3-y2)*(y3-y2)); A = (b*b+c*c-a*a)/( 2 *b*c); B = (a*a+c*c-b*b)/( 2 *a*c); C = (b*b+a*a-c*c)/( 2 *b*a); if (A> 0 &&B> 0 &&C> 0 ) { System.out.println( "false false true" ); //锐角 return ; } else if ((Math.abs(b*b+c*c-a*a)<= 0.000001 )||(Math.abs(a*a+c*c-b*b)<= 0.000001 )||(Math.abs(b*b+a*a-c*c)<= 0.000001 )) { System.out.println( "false true false" ); //直角 return ; } else { System.out.println( "true false false" ); //钝角 return ; } } public void jiaodian() { double k1,k2,a1= 0 ,b1 = 0 ,c1 = 0 ,S1 = 0 ,S2 = 0 ,C = 0 ,B = 0 ,A = 0 ; double X1,Y1,X2,Y2; X1 = (y3*x2*x4-x3*y4*x2-y3*x1*x4+y4*x1*x3-y1*x4*x2+y2*x4*x1+y1*x2*x3-y2*x1*x3)/(x4*y2-x4*y1-x3*y2+x3*y1-x2*y4+x2*y3+x1*y4-x1*y3); Y1 = (-y2*x4*y3+y2*x3*y4+y3*x4*y1-y4*x3*y1+y4*x2*y1-y1*x2*y3-y4*x1*y2+y2*x1*y3)/(y4*x2-y4*x1-y3*x2+x1*y3-y2*x4+y2*x3+y1*x4-y1*x3); X2 = (y3*x2*x5-x3*y5*x2-y3*x1*x5+y5*x1*x3-y1*x5*x2+y2*x5*x1+y1*x2*x3-y2*x1*x3)/(x5*y2-x5*y1-x3*y2+x3*y1-x2*y5+x2*y3+x1*y5-x1*y3); Y2 = (-y2*x5*y3+y2*x3*y5+y3*x5*y1-y5*x3*y1+y5*x2*y1-y1*x2*y3-y5*x1*y2+y2*x1*y3)/(y5*x2-y5*x1-y3*x2+x1*y3-y2*x5+y2*x3+y1*x5-y1*x3); k1 = (y2-y1)/(x2-x1); k2 = (y4-y3)/(x4-x3); if (chonghe(x1,y1,x2,y2)||chonghe(x3,y3,x4,y4)) { System.out.println( "points coincide" ); } else { if (k1==k2||(x1==x2&&x3==x4)) { return ; } else { // System.out.println(x+","+y+" "+isinline(x,y)); a1 = Math.sqrt((x3-X1)*(x3-X1)+(y3-Y1)*(y3-Y1)); b1 = Math.sqrt((x3-X2)*(x3-X2)+(y3-Y2)*(y3-Y2)); c1 = Math.sqrt((X1-X2)*(X1-X2)+(Y1-Y2)*(Y1-Y2)); A = Math.sqrt((x4-x5)*(x4-x5)+(y4-y5)*(y4-y5)); B = Math.sqrt((x3-x5)*(x3-x5)+(y3-y5)*(y3-y5)); C = Math.sqrt((x3-x4)*(x3-x4)+(y3-y4)*(y3-y4)); S1 = 0.5 * a1 * b1 * Math.sqrt( 1 -((b1*b1+c1*c1-a1*a1)/ 2 *b1*c1)*((b1*b1+c1*c1-a1*a1)/ 2 *b1*c1)); S2 = 0.5 * B * C * Math.sqrt( 1 -((B*B+C*C-A*A)/ 2 *B*C)*((B*B+C*C-A*A)/ 2 *B*C)); if (S1<S2) System.out.println( "2 " +S1+ " " +S2); else System.out.println( "2 " +S2+ " " +S1); } } } public void fivepointstriangle() { // double a,b,c,x,y,X,Y; boolean judge = false ; // a = Math.sqrt((x3-x4)*(x3-x4)+(y3-y4)*(y3-y4)); // b = Math.sqrt((x3-x5)*(x3-x5)+(y3-y5)*(y3-y5)); // c = Math.sqrt((x4-x5)*(x4-x5)+(y4-y5)*(y4-y5)); if (x1==x2&&y1==y2) System.out.print( "points coincide" ); else { if ((x3==x4&&y3==y4)||(x3==x5&&y3==y5)||(x4==x5&&y4==y5)||(x3==x4&&x3==x5)) judge= false ; else { if (x3==x4||x3==x5||x4==x5) judge= true ; else { double slope1=(y3-y4)/(x3-x4); double slope2=(y3-y5)/(x3-x5); if (slope1!=slope2) judge= true ; } } if (judge) { double distance1=((y1-y2)*x3+(x2-x1)*y3+x1*y2-y1*x2)/Math.sqrt((y1-y2)*(y1-y2)+(x1-x2)*(x1-x2)); double distance2=((y1-y2)*x4+(x2-x1)*y4+x1*y2-y1*x2)/Math.sqrt((y1-y2)*(y1-y2)+(x1-x2)*(x1-x2)); double distance3=((y1-y2)*x5+(x2-x1)*y5+x1*y2-y1*x2)/Math.sqrt((y1-y2)*(y1-y2)+(x1-x2)*(x1-x2)); if ((distance1> 0 &&distance2> 0 &&distance3> 0 )||(distance1< 0 &&distance2< 0 &&distance3< 0 )) System.out.print( "0" ); else if ((distance1== 0 &&distance2*distance3> 0 )||(distance2== 0 &&distance1*distance3> 0 )||(distance3== 0 &&distance1*distance2> 0 )) System.out.print( "1" ); else if ((distance1== 0 &&distance2== 0 )||(distance1== 0 &&distance3== 0 )||(distance2== 0 &&distance3== 0 )) System.out.print( "The point is on the edge of the triangle" ); else { jiaodian(); } } else System.out.print( "data error" ); } } public void fourpoints(){ } public void input( double a, double b) { x = a; y = b; } //读取x的值// public double read_x() { return x; } //读取y的值// public double read_y() { return y; } //计算两点的距离// public double caluate_distance(Point p) { return Math.sqrt((x-p.x )*(x-p.x )+(y-p.y )*(y-p.y)); } //检查线的两点是否重合// public boolean chack_point(Point p) { boolean wssa = false ; if (Math.abs(x-p.read_x())<1e- 15 &&Math.abs(y-p.read_y())<1e- 15 ) { wssa = true ; } return wssa; } } class Line { Point p1 = new Point(); Point p2 = new Point(); //检查线段的斜率是否存在// public boolean chack_slope() { boolean wssa = true ; if (Math.abs(p1.read_x()-p2.read_x())<1e- 15 ) { wssa = false ; } return wssa; } //计算线段的斜率// public double caluate_slope() { return (p1.read_x()-p2.read_y())/(p1.read_x()-p2.read_y()); } //计算点到直线的距离// public double caluate_distance(Point a) { double distance ; if (if_on_line(a)){ distance = 0 ; } else { distance = Math.abs(a.read_x()*p1.read_y()+p1.read_x()*p2.read_y()+p2.read_x()*a.read_y()-a.read_x()*p2.read_y()-p1.read_x()*a.read_y()-p2.read_x()*p1.read_y())/p1.caluate_distance(p2); } return distance ; } //判断点是否再直线上// public boolean if_on_line(Point p) { boolean jes = false ; Line l1 = new Line(); Line l2 = new Line(); l1.p1 = p1; l1.p2 = p; l2.p1 = p2; l2.p2 = p; if (l1.caluate_slope()==l2.caluate_slope()) { jes = true ; } return jes; } //判断点是否在线段内// //在线段内返回true,在线段外返回false// public boolean if_in_line(Point p) { boolean jes = true ; if (p.caluate_distance(p1)>p1.caluate_distance(p2)||p.caluate_distance(p2)>p1.caluate_distance(p2)) { jes = false ; } return jes; } //判断两直线是否平行// //若两直线平行返回1,若两直线重合返回0,若两直线相交返回-1 public int if_parallel(Line l) { int cnt ; double x1 = (p1.read_x()-p2.read_x())*(l.p1.read_x()-l.p2.read_x())+(p1.read_y()-p2.read_y())*(l.p1.read_y()-l.p2.read_y()); if (x1/(p1.caluate_distance(p2)*l.p1.caluate_distance(p2))!= 1 ) { cnt=- 1 ; } else { if (l.caluate_distance(p1)== 0 ) { cnt= 0 ; } else { cnt= 1 ; } } return cnt; } //计算两直线交点,返回Point// public Point caluate_intersection(Line a){ Point p = new Point(); double dx1 = p1.read_x()-p2.read_x(); double dx2 = a.p1.read_x()-a.p2.read_x(); double dy1 = p1.read_x()-p2.read_x(); double dy2 = a.p1.read_x()-a.p2.read_x(); double mid1 = dy1/dx1; double mid2 = dy2/dx2; double rx = (a.p2.read_y()-p2.read_y()-a.p2.read_y()*mid2+p2.read_y()*mid1)/(mid1-mid2); double ry = (rx-p2.read_x())*mid1+p2.read_y(); p.input(rx, ry); return p; } } class Triangle { Point p1 = new Point(); Point p2 = new Point(); Point p3 = new Point(); //检查三点是否构成三角形// //若构成三角形返回false,若不构成三角形返回true// public boolean chack_triangle() { boolean err = true ; if (Math.abs(p1.caluate_distance(p2)-p1.caluate_distance(p3))<p2.caluate_distance(p3)&&Math.abs(p1.caluate_distance(p3)+p1.caluate_distance(p2))>p2.caluate_distance(p3)){ err = false ; } return err ; } //判断是否为等边三角形,或等腰三角形// //若为等腰三角形,返回0// //若为等边三角形,返回1// public int shape_line_triangle() { int shape = 0 ; if (Math.abs(p1.caluate_distance(p2)-p1.caluate_distance(p3))<1e- 15 &&Math.abs(p2.caluate_distance(p1)-p2.caluate_distance(p3))<1e- 15 ) { shape = 1 ; } return shape; } //计算三角形面积,返回面积// public double caluate_S() { return Math.abs(p1.read_x()*p2.read_y()+p2.read_x()*p3.read_y()+p3.read_x()*p1.read_y()-p1.read_x()*p3.read_y()-p2.read_x()*p1.read_y()-p3.read_x()*p2.read_y())/ 2 ; } //计算三角形的周长,返回周长// public double caluate_C() { return p1.caluate_distance(p2)+p1.caluate_distance(p3)+p2.caluate_distance(p3); } //计算三角形的重心坐标,返回Point// public Point caluate_gravity_point() { Point p = new Point(); double dx = (p1.read_x()+p2.read_x()+p3.read_x())/ 3 ; double dy = (p1.read_y()+p2.read_y()+p3.read_y())/ 3 ; p.input(dx, dy); return p; } //判断三角形是锐角三角形还是直角三角形或钝角三角形// //若是锐角三角形返回1,若是直角三角形返回0,若是钝角三角形则返回-1// public int shape_horn_triangle() { int shape ; double j1 = (p2.read_x()-p1.read_x())*(p3.read_x()-p1.read_x())+(p2.read_y()-p1.read_y())*(p3.read_y()-p1.read_y()); double j2 = (p3.read_x()-p2.read_x())*(p1.read_x()-p2.read_x())+(p3.read_y()-p2.read_y())*(p1.read_y()-p2.read_y()); double j3 = (p1.read_x()-p3.read_x())*(p2.read_x()-p3.read_y())+(p1.read_y()-p3.read_y())*(p2.read_y()-p3.read_y()); if (j1< 0 ||j2< 0 ||j3< 0 ) { shape = 1 ; } else if (j1== 0 ||j2== 0 ||j3== 0 ) { shape = 0 ; } else { shape = - 1 ; } return shape; } //计算直线与三角形的交点// //返回交点个数// public int caluate_sum_intersection(Line a) { int sum = 0 ; Line l1 = new Line(); l1.p1=p1;l1.p2=p2; Line l2 = new Line(); l2.p1=p1;l2.p2=p3; Line l3 = new Line(); l3.p1=p2;l3.p2=p3; if (l1.if_parallel(a)== 1 ) { Point point1 = a.caluate_intersection(l2); if (l2.if_in_line(point1)) { sum++; } Point point2 = a.caluate_intersection(l3); if (l3.if_in_line(point2)) { sum++; } } else if (l2.if_parallel(a)== 1 ) { Point point1 = a.caluate_intersection(l1); if (l1.if_in_line(point1)) { sum++; } Point point2 = a.caluate_intersection(l3); if (l3.if_in_line(point2)) { sum++; } } else if (l3.if_parallel(a)== 1 ) { Point point1 = a.caluate_intersection(l1); if (l1.if_in_line(point1)) { sum++; } Point point2 = a.caluate_intersection(l2); if (l2.if_in_line(point2)&&point1.chack_point(point2)) { sum++; } } else { Point point1 = a.caluate_intersection(l1); if (l1.if_in_line(point1)) { sum++; } Point point2 = a.caluate_intersection(l2); if (l2.if_in_line(point2)&&point1.chack_point(point2)) { sum++; } Point point3 = a.caluate_intersection(l2); if (l2.if_in_line(point3)&&point1.chack_point(point3)&&point2.chack_point(point3)) { sum++; } } return sum; } //判断点是否再三角形内部// public boolean if_inside(Point a) { boolean rea = false ; Line l1 = new Line(); l1.p1=p1; l1.p2=a; Line l2 = new Line(); l2.p1=p2; l2.p2=a; Line l3 = new Line(); l3.p1=p3; l3.p2=a; Line l4 = new Line(); l4.p1=p1; l4.p2=p2; Line l5 = new Line(); l5.p1=p2; l5.p2=p3; Line l6 = new Line(); l6.p1=p3; l6.p2=p1; if (!l5.if_in_line(l1.caluate_intersection(l5))||!l4.if_in_line(l3.caluate_intersection(l4))||!l6.if_in_line(l2.caluate_intersection(l6))) { rea = true ; } return rea; } } |
总结:一开始写这道题时,想着只用点类来进行,但是在最后两个需求上,单用点类非常难实现,在前面进行字符串分割,以及前三个需求时,点类可以用的很简单,但是到了四五需求,不知道该如何设计方法,参数传递彻底搞晕,最后也尝试设计线类以及三角形类,但还是没能完成该题。
SourceMonitor分析图:
三、踩坑心得
1.这四道题我并没有全拿满分,有部分题目的部分测试点过不去,在字符串的处理上有很多地方做的不好,导致输入数据格式存在错误。
2.对类的认识还不是很充分,有很多在Main中的其实可以将其封装,导致代码冗长易出错
3.在计算上不是数学上的范围,例如判断直角三角形,应该是两边平方和减第三边平方小于一个极小值,而不是等于0,题目中就有一个测试点是关于此的,我改了很久。
4.不要怕麻烦,无论是学习正则表达式还是去多设计类,能用类的就用类,到后期会越来越方便。
四、改进建议
1.switch语句的复杂度比if语句更低,在之后的编码中能用switch替代就尽量不使用if。
2.编写代码前提前构建好类图,效率更高
3.多用类,多用方法,不要一直Main
4.String类型判断使用正则表达式很快
5.边写代码边调试,多写注释
五、总结
第一阶段的学习已经过去,我逐渐明白Java和c的相似以及不同,基本语法虽大体相同,但角度却不同了。我更熟练的运用字符串及其相关函数,并且慢慢习惯运用方法和类,但是并不熟练。对于整体的题目设计方面还需要大大加强,这样才能简化运算以及代码,可读性也会更强。另外,一定要合理规划好时间,不要拖拉,作业发布最好就快速开始,遇到问题积极寻求帮助,多想多学多问,问题总会解决的
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