【python】一个简单的贪婪爬虫

这个爬虫的作用是,对于一个给定的url,查找页面里面所有的url连接并依次贪婪爬取

 

主要需要注意的地方:

1.lxml.html.iterlinks()  可以实现对页面所有url的查找

2.获取页面要设置超时,否则遇到没有响应的页面,代码容易卡死

3.对所有异常的捕获

4.广度优先搜索实现

 

具体代码如下:

#!/usr/bin/env python
#encoding:utf8

#这是一个爬虫代码,从初始url页面中查找所有的url并根据广度优先的顺序依次贪婪爬取
#爬取的页面以1.html,2.html...的方式命名
#author:匡子语
import re import time import lxml.html import urllib2 from collections import deque class ScrawURL: def __init__(self): self.total = 50000 #要获取的页面数 self.urls = ["http://www.cnblogs.com/"] #初始url self.html_num = 13047 #当前存储的是第几个页面 self.url_num = 0 #当前要爬取的url在urls中的位置 def getHtml(self, url): print "url:%s" % url user_agent = 'Mozilla/4.0 (compatible; MSIE 5.5; Windows NT)' headers = { 'User-Agent' : user_agent } try: request = urllib2.Request(url, headers = headers) response = urllib2.urlopen(request, timeout=5) #要设置timeout,有时页面长时间无法响应不加timeout会导致程序卡死 content = response.read() self.html_num += 1 name = "htmls/%d.html" % self.html_num with open(name, "w") as f: f.write(content) print self.html_num return content except urllib2.HTTPError, e: return '' except urllib2.URLError, e: return '' except Exception, ex: #对于所有异常形式,都返回空内容 return '' def getUrl(self, content): try: print "getUrl" html = lxml.html.fromstring(content) links = lxml.html.iterlinks(html) #这个函数可以自动获取页面中的所有url,非常好用 urls = [] for link in links: if "http" in link[2]: urls.append(link[2]) return urls except Exception, ex: return [] def scrawl(self): #广度优先爬取 print "scrawl" while len(self.urls) < self.total and len(self.urls) > self.url_num: #获取足够的url url = self.urls[self.url_num] self.url_num += 1 content = self.getHtml(url) if content: urls = self.getUrl(content) if urls: for url in urls: if url not in self.urls: #对于已经爬取过的url跳过 self.urls.append(url) while self.html_num < self.total and len(self.urls) > 0: #获取足够的页面 url = self.urls[self.url_num] self.url_num += 1 self.getHtml(url) if __name__ == "__main__": surl = ScrawURL() surl.scrawl()

 

posted @ 2016-07-27 09:48  匡子语  阅读(544)  评论(0编辑  收藏  举报