[LeetCode] 25. K 个一组翻转链表
方法一:;来自大佬
public ListNode reverseKGroup(ListNode head, int k) { ListNode dummy = new ListNode(0); dummy.next = head; ListNode pre = dummy; ListNode end = dummy; while (end.next != null) { for (int i = 0; i < k && end != null; i++) end = end.next; if (end == null) break; ListNode start = pre.next; ListNode next = end.next; end.next = null; pre.next = reverse(start); start.next = next; pre = start; end = pre; } return dummy.next; } private ListNode reverse(ListNode head) { ListNode pre = null; ListNode curr = head; while (curr != null) { ListNode next = curr.next; curr.next = pre; pre = curr; curr = next; } return pre; } 作者:reals 链接:https://leetcode-cn.com/problems/reverse-nodes-in-k-group/solution/tu-jie-kge-yi-zu-fan-zhuan-lian-biao-by-user7208t/ 来源:力扣(LeetCode) 著作权归作者所有。商业转载请联系作者获得授权,非商业转载请注明出处。
前几天都在gy,在外面都没时间写拉,补回来