摘要: select a.id, a.username, substring_index(substring_index(a.course, '|', b.help_topic_id + 1), '|', -1) course from student a JOIN mysql.help_topic b O 阅读全文
posted @ 2020-04-03 17:31 贝宝纸 阅读(104) 评论(0) 推荐(0) 编辑