8位无符号整数点分式版本

1、点分式版本

　　版本 1.0.1.800 ，每个数字占用2个字节，一个8个字节组成8位无符号整数

　　利用下面的脚本进行校验和转换

　　

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#!/usr/local/bin/python3 # -*- coding: utf-8 -*- __author__ = 'qqvipfunction'   import re   def versionToUInt64(version):     version = version.strip()     pattern = re.compile(r'^(\d+)\.(\d+)\.(\d+)\.(\d+)$')     match = pattern.match(version)     if match:         uint16_max = 2<<16 - 1         uint64_tuple = match.groups()         value0 = int(uint64_tuple[0])         value1 = int(uint64_tuple[1])         value2 = int(uint64_tuple[2])         value3 = int(uint64_tuple[3])         if value0 <= uint16_max and value1 <= uint16_max and value2 <= uint16_max and value3 <= uint16_max:             value = (value0<<48|value1<<32|value2<<16|value3)             return str(value)     return "invalid formate version"   if __name__ == '__main__':       while True:         version = input("version:")         version = version.strip()         print("version " + "\"" + version + "\" " + "to uint64 = " + versionToUInt64(version))