03 2015 档案

大端还是小端
摘要：//way 1union{ unsigned long biths; unsigned char bytes[4];} theValue;//way 2ndtypedef char* bytePointer;void showBytes(bytePointer p, int len){ in... 阅读全文

posted @ 2015-03-30 22:02 dotdog 阅读(254) 评论(0) 推荐(0)

c语言程序设计 字符串拷贝拷贝演变与初衷
摘要：/*v1*/void strcpy(char *s, char *t){ int i; i = 0; while((s[i] = t[i]) != '\0') i++;}/*v2*/void strcpy(char *s, char *t){ while((*s = *t) != ... 阅读全文

posted @ 2015-03-28 13:07 dotdog 阅读(203) 评论(0) 推荐(0)

内存 匹配串
摘要：/*返回t在s中的位置，若未找到则返回－1*/int strindex(char* s,char* t){ int i, j, k; for(i = 0; s[i] != '\0'; i++) for(k = i,j = 0; s[k]=t[j] && s[k]!='\0'; k++,... 阅读全文

posted @ 2015-03-27 22:21 dotdog 阅读(140) 评论(0) 推荐(0)

多态 C2
摘要：class apple {public: ~apple(){ std::cout << "~apple()" << std::endl;}};class banana : public apple { ~banana(){ std::cout << "~banana()" << std::e... 阅读全文

posted @ 2015-03-27 21:43 dotdog 阅读(111) 评论(0) 推荐(0)

多态 C1
摘要：1 class base { 2 public: 3 virtual void test1() { std::cout << "base::test1"<< std::endl; } 4 void test2(){ std::cout << "base::test2"; } ... 阅读全文

posted @ 2015-03-27 21:26 dotdog 阅读(120) 评论(0) 推荐(0)

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