图片上传功能是网站制作很重要的环节，我们来看看如下代码：
upload.htm
' 上传页面
<html>
<body>
<p align="center">制作之图片上传</p>
<center>
<form name="mainForm" enctype="multipart/form-data"
' 这个Form属性是得到上传的数据的关键
action="process.asp" method=post>
<input type=file name=mefile><br>
<input type=submit name=ok value="上传">
</form>
</center>
</body>
</html>
process.asp
' 处理浏览器中送来的数据
<%
response.buffer=true
formsize=request.totalbytes
formdata=request.binaryread(formsize)
bncrlf=chrB(13) & chrB(10)
divider=leftB(formdata,clng(instrb(formdata,bncrlf))-1)
datastart=instrb(formdata,bncrlf & bncrlf)+4
dataend=instrb(datastart+1,formdata,divider)-datastart
mydata=midb(formdata,datastart,dataend)
set connGraph=server.CreateObject("ADODB.connection")
connGraph.ConnectionString="driver={Microsoft Access Driver (*.mdb)};
DBQ=" & server.MapPath("images.mdb") & ";uid=;PWD=;"
connGraph.Open
set rec=server.createobject("ADODB.recordset")
rec.Open "SELECT * FROM [images] where id is null",connGraph,1,3
rec.addnew
rec("img").appendchunk mydata
rec.update
rec.close
set rec=nothing
set connGraph=nothing
%>
showimg.asp
' 网站制作显示图片
<%
set connGraph=server.CreateObject("ADODB.connection")
connGraph.ConnectionString="driver={Microsoft Access Driver (*.mdb)};
DBQ=" & server.MapPath("images.mdb") & ";uid=;PWD=;"
connGraph.Open
set rec=server.createobject("ADODB.recordset")
strsql="select img from images where id=" & trim(request("id"))
rec.open strsql,connGraph,1,1
Response.ContentType = "image/*"
' 在输出到浏览器之前一定要指定Response.ContentType = "image/*",以便正常显示图片
Response.BinaryWrite rec("img").getChunk(7500000)
rec.close
set rec=nothing
set connGraph=nothing
%>
