- 简介
Wrapper : 条件构造抽象类,最顶端父类
AbstractWrapper : 用于查询条件封装,生成 sql 的 where 条件
QueryWrapper : 查询条件封装
UpdateWrapper : Update 条件封装
AbstractLambdaWrapper : 使用Lambda 语法
LambdaQueryWrapper :用于Lambda语法使用的查询Wrapper
LambdaUpdateWrapper : Lambda 更新封装Wrapper
@SpringBootTest
public class MyBatisPlusWrapperTest {
@Autowired
private UserMapper userMapper;
@Test
public void test01(){
//查询用户名包含a,年龄在20到30之间,邮箱信息不为null的用户信息
//SELECT uid AS id,user_name AS name,age,email,is_deleted FROM t_user WHERE is_deleted=0 AND (user_name LIKE ? AND age BETWEEN ? AND ? AND email IS NOT NULL)
QueryWrapper<User> queryWrapper = new QueryWrapper<>();
queryWrapper.like("user_name", "a")
.between("age", 20, 30)
.isNotNull("email");
List<User> list = userMapper.selectList(queryWrapper);
list.forEach(System.out::println);
}
}
@Test
public void test02(){
//查询用户信息,按照年龄的降序排序,若年龄相同,则按照id升序排序
//SELECT uid AS id,user_name AS name,age,email,is_deleted FROM t_user WHERE is_deleted=0 ORDER BY age DESC,uid ASC
QueryWrapper<User> queryWrapper = new QueryWrapper<>();
queryWrapper.orderByDesc("age")
.orderByAsc("uid");
List<User> list = userMapper.selectList(queryWrapper);
list.forEach(System.out::println);
}
@Test
public void test03(){
//删除邮箱地址为null的用户信息
//UPDATE t_user SET is_deleted=1 WHERE is_deleted=0 AND (email IS NULL)
QueryWrapper<User> queryWrapper = new QueryWrapper<>();
queryWrapper.isNull("email");
int result = userMapper.delete(queryWrapper);
System.out.println("result:"+result);
}
@Test
public void test04(){
//将(年龄大于20并且用户名中包含有a)或邮箱为null的用户信息修改
//UPDATE t_user SET user_name=?, email=? WHERE is_deleted=0 AND (age > ? AND user_name LIKE ? OR email IS NULL)
QueryWrapper<User> queryWrapper = new QueryWrapper<>();
queryWrapper.gt("age", 20)
.like("user_name", "a")
.or()
.isNull("email");
User user = new User();
user.setName("小明");
user.setEmail("test@atguigu.com");
int result = userMapper.update(user, queryWrapper);
System.out.println("result:"+result);
}
- 优先级2:如果想让条件有先后顺序,可使用lambda
@Test
public void test05(){
//将用户名中包含有a并且(年龄大于20或邮箱为null)的用户信息修改
//lambda中的条件优先执行
//UPDATE t_user SET user_name=?, email=? WHERE is_deleted=0 AND (user_name LIKE ? AND (age > ? OR email IS NULL))
QueryWrapper<User> queryWrapper = new QueryWrapper<>();
queryWrapper.like("user_name", "a")
.and(i->i.gt("age",20).or().isNull("email"));
User user = new User();
user.setName("小红");
user.setEmail("test@atguigu.com");
int result = userMapper.update(user, queryWrapper);
System.out.println("result:"+result);
}
@Test
public void test06(){
//查询用户的用户名、年龄、邮箱信息
//SELECT user_name,age,email FROM t_user WHERE is_deleted=0
QueryWrapper<User> queryWrapper = new QueryWrapper<>();
queryWrapper.select("user_name", "age", "email");
List<Map<String, Object>> maps = userMapper.selectMaps(queryWrapper);
maps.forEach(System.out::println);
}
@Test
public void test07(){
//查询id小于等于100的用户信息
// SELECT uid AS id,user_name AS name,age,email,is_deleted FROM t_user WHERE is_deleted=0
// AND (uid IN (select uid from t_user where uid <= 100))
QueryWrapper<User> queryWrapper = new QueryWrapper<>();
queryWrapper.inSql("uid", "select uid from t_user where uid <= 100");
List<User> list = userMapper.selectList(queryWrapper);
list.forEach(System.out::println);
}
@Test
public void test08(){
//将用户名中包含有a并且(年龄大于20或邮箱为null)的用户信息修改
UpdateWrapper<User> updateWrapper = new UpdateWrapper<>();
updateWrapper.like("user_name", "a")
.and(i -> i.gt("age", 20).or().isNull("email"));
updateWrapper.set("user_name", "小黑").set("email","abc@atguigu.com");
int result = userMapper.update(null, updateWrapper);
System.out.println("result:"+result);
}
@Test
public void test09(){
//SELECT uid AS id,user_name AS name,age,email,is_deleted FROM t_user WHERE is_deleted=0
// AND (user_name LIKE ? AND age <= ?)
String username = "a";
Integer ageBegin = null;
Integer ageEnd = 30;
QueryWrapper<User> queryWrapper = new QueryWrapper<>();
if(StringUtils.isNotBlank(username)){
//isNotBlank判断某个字符创是否不为空字符串、不为null、不为空白符
queryWrapper.like("user_name", username);
}
if(ageBegin != null){
queryWrapper.ge("age", ageBegin);
}
if(ageEnd != null){
queryWrapper.le("age", ageEnd);
}
List<User> list = userMapper.selectList(queryWrapper);
list.forEach(System.out::println);
}
@Test
public void test10(){
String username = "a";
Integer ageBegin = null;
Integer ageEnd = 30;
QueryWrapper<User> queryWrapper = new QueryWrapper<>();
queryWrapper.like(StringUtils.isNotBlank(username), "user_name", username)
.ge(ageBegin != null, "age", ageBegin)
.le(ageEnd != null, "age", ageEnd);
List<User> list = userMapper.selectList(queryWrapper);
list.forEach(System.out::println);
}
@Test
public void test11(){
// SELECT uid AS id,user_name AS name,age,email,is_deleted FROM t_user WHERE is_deleted=0
// AND (user_name LIKE ? AND age <= ?)
String username = "a";
Integer ageBegin = null;
Integer ageEnd = 30;
LambdaQueryWrapper<User> queryWrapper = new LambdaQueryWrapper<>();
queryWrapper.like(StringUtils.isNotBlank(username), User::getName, username)
.ge(ageBegin != null, User::getAge, ageBegin)
.le(ageEnd != null, User::getAge, ageEnd);
List<User> list = userMapper.selectList(queryWrapper);
list.forEach(System.out::println);
}
@Test
public void test12(){
//将用户名中包含有a并且(年龄大于20或邮箱为null)的用户信息修改
LambdaUpdateWrapper<User> updateWrapper = new LambdaUpdateWrapper<>();
updateWrapper.like(User::getName, "a")
.and(i -> i.gt(User::getAge, 20).or().isNull(User::getEmail));
updateWrapper.set(User::getName, "小黑").set(User::getEmail,"abc@atguigu.com");
int result = userMapper.update(null, updateWrapper);
System.out.println("result:"+result);
}