C++的多重继承

有如下的C++代码

#include <iostream>
using namespace std;
class Base
{
    public:
        Base(int i) {cout<<"Base constructor called "<<i<<endl;}
        ~Base(void) {cout<<"Base destructor called"<<endl;}
};

class Base1:public Base
{
    public:
        Base1(int i,int j):Base(j) {cout<<"Base1 constructor called "<<i<<endl;}
        ~Base1(void) {cout<<"Base1 destructor called"<<endl;}
};

class Base2
{
    public:
        Base2(int i) {cout<<"Base2 constructor called "<<i<<endl;}
        ~Base2(void) {cout<<"Base2 destructor called"<<endl;}
};

class Base3
{
    public:
        Base3(int i) {cout<<"Base3 constructor called "<<i<<endl;}
        ~Base3(void) {cout<<"Base3 destructor called"<<endl;}
};

class Derived:public Base2,public Base1,public Base3
{
    Base3 member3;  Base1 member1;  Base2 member2;  Base member;
    public:
        Derived(int i,int a,int b,int c,int d,int e,int f,int g)
            :Base1(g,a),member2(e),member1(g,d),Base2(b),member3(f),Base3(c),member(i)
        {
            cout<<"Derived constructor called "<<i<<endl;
        }
        ~Derived(void) {cout<<"Derived destructor called"<<endl;}
};

int main()
{
    Derived objD(1,2,3,4,5,6,7,8); 
    return 0;
}

用 $ g++ -Wall -o base1 base1.cpp 进行编译

运行 $ ./base1 结果为