Python 分别统计文章不同字符的数据

  • 需求
  • 定义不同的变量代表字符个数，然后根据自带的isX函数进行判断，符合就加1，不断循环即可
  • 代码如下：
  •  1 #coding:utf-8
 2 #__author__ = 'Diva'
 3 
 4 # func
 5 def count_chars(text_input):
 6 
 7     # 首先定义字符个数的变量
 8     int_counts = 0
 9     upper_counts = 0
10     lower_counts = 0
11     blank_counts = 0
12     other_counts = 0
13 
14     #  用自带的isX函数来判断字符
15     for i in range(len(text_input)):
16         text_char = text_input[i]
17         if text_char.isupper():
18             upper_counts += 1
19         elif text_char.islower():
20             lower_counts += 1
21         elif text_char.isdigit():
22             int_counts += 1
23         elif text_char.isspace():
24             blank_counts += 1
25         else:
26             other_counts += 1
27 
28     print('''
29         不同字符的总数分别为：
30         upper_counts = %d,
31         lower_counts = %d,
32         int_counts = %d,
33         blank_counts = %d,
34         other_counts = %d '''
35         % (upper_counts, lower_counts, int_counts, blank_counts, other_counts)
36         )
37 
38 # main
39 if __name__ == '__main__':
40     with open('aa.txt', 'r') as f:
41         text = f.read()
42         count_chars(text)
  • 测试结果：

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posted @ 2017-09-12 13:27  _七杀  阅读(1058)  评论(0)  编辑  收藏  举报