转置矩阵-python

  

ego=[]
era=[]
for b in range(1,10):
    ego.append(b)
    if not b%3:
        era.append(ego)
        ego=[]
        # ego.clear()
print(era)

for b in range(len(era[0])):
    for p in range(b):
        era[b][p],era[p][b]=era[p][b],era[b][p]
print(era)

for b in range(len(era[0])):
    for p in range(b+1,len(era[0])):
        era[p][b],era[b][p]=era[b][p],era[p][b]
print(era)

 

posted @ 2020-08-23 01:22  ascertain  阅读(149)  评论(0编辑  收藏  举报