bash 脚本exercise

  1 #!/bin/env sh
  2 
  3 declare -i max=0
  4 declare -i min=32765
  5 declare -a zz
  6 
  7 for x in `seq 0 1 9`;do
  8         zz[x]=$RANDOM
  9         [ ${zz[x]} -gt $max ] && max=${zz[x]}
 10         [ ${zz[x]} -lt $min ] && min=${zz[x]}
 11 done
 12 
 13 echo ${zz[@]}
 14 echo $max,$min
 1 #!/bin/env sh
 2 
 3 declare -a bb
 4 declare -i sum=0
 5 
 6 bb=(/var/log/*.log)
 7 
 8 for x in `seq 0 2 $[${#bb[*]}-1]`;do
 9     let sum+=`cat ${bb[x]}|wc --lines`
10 done
11 
12 echo $sum
 1 #!/bin/env sh
 2 
 3 declare -a pp
 4 declare -i sum
 5 
 6 pp=(/var/log/*.log)
 7 
 8 for b in `seq 0 1 $[${#pp[*]}-1]`;do
 9     if [ $[b%2] -ne 0 ];then
10         continue
11     fi
12 
13     let sum+=`wc --lines ${pp[b]}|awk '{print $1}'`
14 done
15 
16 echo ${pp[*]},$sum

 

${bb[*]:5:3}

数组切片${array[@]:offset:number}

数组亦支持反向索引

  echo ${array[-1]}

  echo ${array[-2]}

追加元素

  array[${#array[*]}]="variable"

删除数组元素

  unset array[index]

关联数组

  declare -A array_name

 

显示最后一个磁盘信息

 

1 #!/bin/env sh
2 
3 disks=$(fdisk -l /dev/[sh]d[a-z] | grep -o '^Disk /dev/[sh]d[a-z]' | wc --lines)
4 
5 if [[ $disks -eq 1 ]];then
6     fdisk -l /dev/[sh]da
7 else
8     fdisk -l $(fdisk -l /dev/[sh]d[a-z] |grep -o '^Disk /dev/[sh]d[a-z]'|tail -1|cut -d' ' -f2)
9 fi

 

determine root:

#!/bin/env sh

function isRoot(){
        if [ `echo $UID` -ne 0 ];then
                return 5
        else
                return 0
        fi
}

isRoot

if [ $? -ne 0 ];then
        echo "Must be root to execute this script"
        exit 5
else
        echo "Welcom root"
        exit 0
fi

 

nmap-ncat:

Usage: ncat [options] [hostname] [port]
#!/bin/env sh

#cat ip.txt|while read line;do
while read line
do
        nc -zw 2 $line > /dev/null 2>&1
        if [ $? -eq 0 ];then
                echo -e "\033[32;7m$line:success\033[0m"
        else
                echo -e "\033[31;7m$line:fail\033[0m"
        fi
done < $1
~
192.168.31.101 22
192.168.31.102 22
jd.com 443
jd.com 80

 

 



posted @ 2020-05-28 12:26  ascertain  阅读(137)  评论(0编辑  收藏  举报