uva 1368 DNA Consensus String 字符串

这学期离散数学的最后一章刚学了类似的东西

什么decoding function和humming distance手算起来才有点难 编程的话就很水了

 

弱校连萌题目链接:http://acm.bnu.edu.cn/v3/contest_show.php?cid=5772#problem/I

 

#include <cstdio>
#include <cstring>
#include <cstdlib>
#include <iostream>
#include <algorithm>
#include <cmath>
#include <set>
#include <queue>
#include <stack>
#include <map>
#include <vector>

using namespace std;

typedef long long ll;
typedef unsigned long long ull;
typedef pair<int, int> P;

const int maxn = 20;

char a[55][1010];
char b[1010];

const char ch[] = {'A', 'C', 'G', 'T'};

int main()
{
    //freopen("in.txt", "r", stdin);
    //freopen("out.txt", "w", stdout);

    int T;
    scanf("%d", &T);


    while(T--)
    {
        int ans = 0;

        int m, n;
        scanf("%d%d", &m, &n);

        for(int i = 0; i < m; i++)
            scanf("%s", a[i]);

        int cnt[4];

        for(int i = 0; i < n; i++)
        {
            memset(cnt, 0, sizeof(cnt));

            for(int j = 0; j < m; j++)
            {
                int k = 0;
                while(ch[k] != a[j][i])
                    k++;
                cnt[k]++;
            }

            int maxnum = 0;
            for(int j = 0; j < 4; j++)
                if(cnt[j] > maxnum)
                    maxnum = cnt[j];

            for(int j = 0; j < 4; j++)
            {
                if(cnt[j] == maxnum)
                {
                    b[i] = ch[j];
                    ans += m - maxnum;
                    break;
                }
            }

        }
        b[n] = '\0';

        printf("%s\n", b);
        printf("%d\n", ans);
    }

    return 0;
}

 

posted @ 2015-01-31 12:29  地鼠地鼠  阅读(157)  评论(0编辑  收藏  举报