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摘要： #!/bin/bash for (( i=1;i<=9;i++)) do for ((j=1;j<=i;j++)) do let sum=i*j printf "%-8s" $j"x"$i=$sum done echo done #!/bin/bash for(( i=1 ;i<=9;i++ )) 阅读全文

摘要： i = 1while i <= 9: i += 1 j = 1 while j <= i-1: print("{}*{}=".format(j,i-1),j*(i-1),sep='',end=' ') j += 1 print('') for i in range(1,10): for y in r 阅读全文