ZOJ 4070 - Function and Function - [签到题][2018 ACM-ICPC Asia Qingdao Regional Problem M]
题目链接:http://acm.zju.edu.cn/onlinejudge/showContestProblem.do?problemId=5840
Time Limit: 1 Second Memory Limit: 65536 KB
If we define $f(0)=1,f(1)=0,f(4)=1,f(8)=2,f(16)=1 \cdots$, do you know what function $f$ means?
Actually, $f(x)$ calculates the total number of enclosed areas produced by each digit in $x$. The following table shows the number of enclosed areas produced by each digit:
Enclosed Area | Digit | Enclosed Area | Digit |
---|---|---|---|
0 | 1 | 5 | 0 |
1 | 0 | 6 | 1 |
2 | 0 | 7 | 0 |
3 | 0 | 8 | 2 |
4 | 1 | 9 | 1 |
For example, $f(1234)=0+0+0+1=1$, and $f(5678)=0+1+0+2=3$.
We now define a recursive function by the following equations:
For example, $g^2(1234)=f(f(1234))=f(1)=0$, and $g^2(5678)=f(f(5678))=f(3)=0$.
Given two integers $x$ and $k$, please calculate the value of $g^k(x)$.
题解:
(浙大出题就是良心,又稳又好。)
求 $k$ 层嵌套的 $f(x)$,因为几层 $f(x)$ 下去 $x$ 很快就变成 $0$ 或者 $1$ 了,这个时候,可以根据 $x$ 外面还剩下多少层 $f$ 直接返回 $0$ 或者 $1$。
AC代码:
#include<bits/stdc++.h> using namespace std; int fx[10]={1,0,0,0,1,0,1,0,2,1}; int x,k; int f(int x) { int res=0; do{ res+=fx[x%10]; x/=10; }while(x); return res; } int g(int k,int x) { while(k--) { x=f(x); if(x==0) return k%2; if(x==1) return 1-k%2; } return x; } int main() { int T; cin>>T; while(T--) { scanf("%d%d",&x,&k); printf("%d\n",g(k,x)); } }