Codeforces 1154 - A/B/C/D/E/F/G - (Undone)
链接:https://codeforces.com/contest/1154
A - Restoring Three Numbers - [水]
#include<bits/stdc++.h> using namespace std; int a[4]; int main() { cin>>a[0]>>a[1]>>a[2]>>a[3]; sort(a,a+4); for(int i=0;i<=2;i++) printf("%d ",a[3]-a[i]); }
B - Make Them Equal - [分类讨论]
#include<bits/stdc++.h> using namespace std; const int maxn=105; int n; int a[maxn]; bool vis[maxn]; bool check(int x,int p) { for(int i=1;i<=n;i++) { if(a[i]+x==p || a[i]==p || a[i]-x==p) continue; return 0; } return 1; } int main() { cin>>n; int cnt=0; for(int i=1;i<=n;i++) { cin>>a[i]; if(!vis[a[i]]) vis[a[i]]=1, cnt++; } if(cnt==1){printf("0\n"); return 0;} if(cnt==2) { int min1=0, min2=0; for(int x=1;x<=100;x++) { if(vis[x]) { if(min1==0) min1=x; else if(min2==0) min2=x; else break; } } int D; if((min2-min1)%2==0) D=(min2-min1)/2; else D=min2-min1; cout<<D<<endl; return 0; } int min1=0, min2=0, min3=0; for(int x=1;x<=100;x++) { if(vis[x]) { if(min1==0) min1=x; else if(min2==0) min2=x; else if(min3==0) min3=x; else break; } } if(min3-min2==min2-min1) { int D=min3-min2; if(check(D,min2)) cout<<D<<endl; else cout<<-1<<endl; } else cout<<-1<<endl; }
C - Gourmet Cat
#include<bits/stdc++.h> using namespace std; typedef long long ll; ll a,b,c; ll run(int st) { ll A=a, B=b, C=c; for(int i=st;i<=7;i++) { if(i==1 || i==4 || i==7) { if(A>0) A--; else return i-st; } else if(i==2 || i==6) { if(B>0) B--; else return i-st; } else if(i==3 || i==5) { if(C>0) C--; else return i-st; } } ll ans=7-st+1; ll num=min(min(A/3,B/2),C/2); ans+=num*7; A-=3*num, B-=2*num, C-=2*num; for(int i=1;;i++) { if(i==1 || i==4 || i==7) { if(A>0) A--; else return ans+i-1; } else if(i==2 || i==6) { if(B>0) B--; else return ans+i-1; } else if(i==3 || i==5) { if(C>0) C--; else return ans+i-1; } } } int main() { cin>>a>>b>>c; ll ans=0; for(int st=1;st<=7;st++) { ll res=run(st); //printf("%d: %I64d\n",st,res); ans=max(ans,res); } cout<<ans<<endl; }
D - Walking Robot - [贪心]
E - Two Teams - [线段树+链表]
F - Shovels Shop - [DP]
G - Minimum Possible LCM - (Undone)
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