diameter - 博客园

2020年12月18日

摘要： Given an array of distinct integers candidates and a target integer target, return a list of all unique combinations of candidates where the chosen nu 阅读全文

posted @ 2020-12-18 16:41 diameter 阅读(87) 评论(0) 推荐(0) 编辑

38. 外观数列 Count and Say

摘要： The count-and-say sequence is a sequence of digit strings defined by the recursive formula: countAndSay(1) = "1" countAndSay(n) is the way you would " 阅读全文

posted @ 2020-12-18 15:34 diameter 阅读(78) 评论(0) 推荐(0) 编辑

37. 解数独 Sudoku Solver

摘要： Write a program to solve a Sudoku puzzle by filling the empty cells. A sudoku solution must satisfy all of the following rules: Each of the digits 1-9 阅读全文

posted @ 2020-12-18 14:44 diameter 阅读(75) 评论(0) 推荐(0) 编辑

2020年12月17日

36. 有效的数独 Valid Sudoku

摘要： Determine if a 9 x 9 Sudoku board is valid. Only the filled cells need to be validated according to the following rules: Each row must contain the dig 阅读全文

posted @ 2020-12-17 17:34 diameter 阅读(98) 评论(0) 推荐(0) 编辑

35. 搜索插入位置 Search Insert Position

摘要： Given a sorted array of distinct integers and a target value, return the index if the target is found. If not, return the index where it would be if i 阅读全文

posted @ 2020-12-17 14:55 diameter 阅读(67) 评论(0) 推荐(0) 编辑

34. 在排序数组中查找元素的第一个和最后一个位置 Find First and Last Position of Element in Sorted Array

摘要： Given an array of integers nums sorted in ascending order, find the starting and ending position of a given target value. If target is not found in th 阅读全文

posted @ 2020-12-17 14:22 diameter 阅读(75) 评论(0) 推荐(0) 编辑

33. 搜索旋转排序数组 Search in Rotated Sorted Array

摘要： You are given an integer array nums sorted in ascending order, and an integer target. Suppose that nums is rotated at some pivot unknown to you before 阅读全文

posted @ 2020-12-17 10:43 diameter 阅读(86) 评论(0) 推荐(0) 编辑

2020年12月16日

32. 最长有效括号 Longest Valid Parentheses

摘要： Given a string containing just the characters '(' and ')', find the length of the longest valid (well-formed) parentheses substring. Input: s = "(()"O 阅读全文

posted @ 2020-12-16 19:16 diameter 阅读(94) 评论(0) 推荐(0) 编辑

2020年12月14日

31. 下一个排列 Next Permutation

摘要： Implement next permutation, which rearranges numbers into the lexicographically next greater permutation of numbers. If such an arrangement is not pos 阅读全文

posted @ 2020-12-14 17:23 diameter 阅读(68) 评论(0) 推荐(0) 编辑

2020年12月13日

30. 串联所有单词的子串 Substring with Concatenation of All Words

摘要： You are given a string s and an array of strings words of the same length. Return all starting indices of substring(s) in s that is a concatenation of 阅读全文

posted @ 2020-12-13 21:15 diameter 阅读(86) 评论(0) 推荐(0) 编辑

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