洛谷-P4011 孤岛营救问题
孤岛营救问题
bfs + 状态压缩
对钥匙的状态进行压缩,然后 bfs 剪枝搜索
#include <iostream>
#include <cstdio>
#include <queue>
using namespace std;
int dp[20][20][1 << 16 | 1];
int dr[20][20][20][20];
int dor[20][20];
const int xi[4] = {0, 0, 1, -1};
const int yi[4] = {1, -1, 0, 0};
int n, m, p;
struct node
{
int x, y, dis, status;
node(){}
node(int _x, int _y, int _dis, int _status){x = _x; y = _y; dis = _dis; status = _status;}
};
inline bool check(int x, int y)
{
return x >= 1 && x <= n && y >= 1 && y <= m;
}
int bfs()
{
int ans = n * m * 100;
queue<node>q;
q.push({1, 1, 0, dor[1][1]});
while(q.size())
{
node now = q.front();
q.pop();
if(now.x == n && now.y == m)
{
ans = now.dis < ans ? now.dis : ans;
continue;
}
int& dis = dp[now.x][now.y][now.status];
if(dis <= now.dis) continue;
dis = now.dis;
for(int i=0; i<4; i++)
{
int xx = now.x + xi[i];
int yy = now.y + yi[i];
if(check(xx, yy))
{
int way = dr[now.x][now.y][xx][yy];
if(way == 0 || (way > 0 && (now.status & (1 << way)) == 0)) continue;
q.push(node(xx, yy, dis + 1, now.status | dor[xx][yy]));
}
}
}
return ans;
}
int main()
{
ios::sync_with_stdio(false);
cin.tie(0);
cout.tie(0);
cin >> n >> m >> p;
for(int i=0; i<=n; i++)
for(int j=0; j<=m; j++)
for(int u=0; u<=n; u++)
for(int v=0; v<=m; v++)
dr[i][j][u][v] = -1;
int temp = n * m * 100;
for(int i=0; i<=n; i++)
for(int j=0; j<=m; j++)
for(int u=1<<(p+2); u>=0; u--)
dp[i][j][u] = temp;
int k;
cin >> k;
while(k--)
{
int ax, ay, bx, by, x;
cin >> ax >> ay >> bx >> by >> x;
dr[ax][ay][bx][by] = x;
dr[bx][by][ax][ay] = x;
}
cin >> k;
while(k--)
{
int x, y, z;
cin >> x >> y >> z;
dor[x][y] |= 1 << z;
}
int ans = bfs();
if(ans == temp)
ans = -1;
cout << ans << endl;
return 0;
}