排序查询

#进阶3:排序查询
/*
引入:
			SELECT * FROM employees;
语法:
				SELECT 查询列表	
				from 表
                               【where 筛选条件】
                                ORDER BY 排序列表【asc|desc】
特点:
1.asc代表的是升序,desc代表的是降序
如果不屑,默认是降序
2.ORDER BY 子句中可以支持单个字段、多个字段、表达式、函数、别名。
3.ORDER BY 子句一般是放在查询语句的最后面,limit子句除外
*/
#案例1:查询员工信息,要求工资从高到低排序
SELECT
	*
FROM
	employees
ORDER BY
	salary DESC;

SELECT
	*
FROM
	employees
ORDER BY
	salary;

#案例2:查询部门编号>=90的员工信息,按入职时间的先后排序
SELECT
	*
FROM
	employees
WHERE
	department_id >= 90
ORDER BY
	hiredate ASC;

#案例3:按年薪的高低显示员工的信息和年薪【按表达式排序】
SELECT
	*, salary * 12 * (1 + IFNULL(commission_pct, 0)) AS 年薪
FROM
	employees
ORDER BY
	salary * 12 * (1 + IFNULL(commission_pct, 0)) DESC;

#案例4:按年薪的高低显示员工的信息和年薪【按表达式排序】
SELECT
	*, salary * 12 * (1 + IFNULL(commission_pct, 0)) AS 年薪
FROM
	employees
ORDER BY
	年薪 DESC;

#案例5:按姓名的长度显示员工的姓名和工资【按函数排序】
SELECT
	LENGTH(last_name) 字节长度,
	last_name,
	salary
FROM
	employees
ORDER BY
	LENGTH(last_name) DESC;

#案例6:查询员工信息,要求先按工资 升序,再按员工编号降序【按多个】
SELECT
	*
FROM
	employees
ORDER BY
	employee_id DESC,
	salary ASC;

#查询员工的姓名和部门号和年薪,按年薪降序排序,按姓名升序
SELECT
	last_name,
	department_id,
	salary * 12 * (1 + IFNULL(commission_pct, 0)) AS 年薪
FROM
	employees
ORDER BY
	年薪 DESC,
	last_name ASC;

#选择工资不在8000到17000的员工的姓名和工资,按工资降序
SELECT
	last_name,
	salary
FROM
	employees
WHERE
	salary NOT BETWEEN 8000
AND 17000
ORDER BY
	salary DESC;

#查询邮箱中包含e的员工信息,并先按邮箱的字节数降序,再按部门号升序
SELECT
	*, LENGTH(email) AS 邮箱长度
FROM
	employees
WHERE
	email LIKE '%e%'
ORDER BY
	LENGTH(email) DESC,
	department_id ASC;

  

posted @ 2020-07-04 10:50  自律即自由-  阅读(160)  评论(0编辑  收藏  举报