DevExpress之TreeList的研究绑定XML文件

上次的递归调用进行对XML文件读取限制比较大，这次静态进行读取，思路还是先把XML读取到DataTable中然后进行绑定，代码入下：

   private DataTable CreatTable()
        {
            DataTable dt = new DataTable();
            dt.Columns.Add("ID");
            dt.Columns.Add("ParentID");
            dt.Columns.Add("Name");
            XmlDocument xmlDoc=new XmlDocument();
            xmlDoc.Load(g_filepath);
            XmlNode rootnode = xmlDoc.DocumentElement;
            dr = dt.NewRow();
            int Id = 1;
            dr["ID"] = Id++;
            dr["ParentID"] = 0;
            dr["Name"] = rootnode.Name.ToString();
            dt.Rows.Add(dr);
            if (rootnode.HasChildNodes)
            {
                XmlNodeList xmlnodelist = rootnode.ChildNodes;
                foreach (XmlNode xmlnode in xmlnodelist)
                {
                    dr = dt.NewRow();
                    dr["ID"] = Id++;
                    dr["ParentID"] = 1;
                    dr["Name"] = xmlnode.Name.ToString();
                    dt.Rows.Add(dr);
                    if (xmlnode.HasChildNodes)
                    {
                        int j = 1;
                        XmlNodeList nodelist = xmlnode.ChildNodes;
                        foreach (XmlNode node in nodelist)
                        {
                            int pId=Id;
                            dr = dt.NewRow();
                            dr["ID"] = Id++;
                            dr["ParentID"] =pId-j ;
                            dr["Name"] =node.Name.ToString();
                            dt.Rows.Add(dr);
                            j++;
                            if (node.HasChildNodes)
                            {
                                int i = 1;
                                XmlNodeList list = node.ChildNodes;
                                foreach (XmlNode Node in list)
                                {
                                    if (Node.NodeType == XmlNodeType.Text)
                                    {
                                        continue;
                                    }
                                    else
                                    {
                                        int ppId = Id;
                                        dr = dt.NewRow();
                                        dr["ID"] = Id++;
                                        dr["ParentID"] = ppId - i;
                                        dr["Name"] = Node.Name.ToString();
                                        dt.Rows.Add(dr);
                                        i++;
                                        j++;
                                    }
                                }
                            }
                            else
                            {
                                continue;
                            }
                        }
                    }
                    else
                    {
                        continue;
                    }

                }
            }
            return dt;
        }