【Leetcode】Clone Graph
Clone an undirected graph. Each node in the graph contains a label
and a list of its neighbors
.
OJ's undirected graph serialization:
Nodes are labeled uniquely.
We use#
as a separator for each node, and ,
as a separator for node label and each neighbor of the node.
As an example, consider the serialized graph {0,1,2#1,2#2,2}
.
The graph has a total of three nodes, and therefore contains three parts as separated by #
.
- First node is labeled as
0
. Connect node0
to both nodes1
and2
. - Second node is labeled as
1
. Connect node1
to node2
. - Third node is labeled as
2
. Connect node2
to node2
(itself), thus forming a self-cycle.
Visually, the graph looks like the following:
1 / \ / \ 0 --- 2 / \ \_/
1 /** 2 * Definition for undirected graph. 3 * struct UndirectedGraphNode { 4 * int label; 5 * vector<UndirectedGraphNode *> neighbors; 6 * UndirectedGraphNode(int x) : label(x) {}; 7 * }; 8 */ 9 class Solution { 10 public: 11 UndirectedGraphNode *cloneGraph(UndirectedGraphNode *node) { 12 unordered_map<UndirectedGraphNode *, UndirectedGraphNode *> map; 13 if (node == nullptr) { 14 return nullptr; 15 } 16 return clone(node, map); 17 } 18 private: 19 UndirectedGraphNode *clone(UndirectedGraphNode *node, 20 unordered_map<UndirectedGraphNode *, UndirectedGraphNode *> &map) { 21 if (map.find(node) != map.end()) { 22 return map[node]; 23 } 24 UndirectedGraphNode *new_node = new UndirectedGraphNode(node->label); 25 map[node] = new_node; 26 for (auto n : node->neighbors) { 27 new_node->neighbors.push_back(clone(n, map)); 28 } 29 return new_node; 30 } 31 };
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