二分法合并K个有序数组

# 二分合并k个有序数组
nums1 = [2,3,18,23,118,283]
nums2 = [4,7,8,19,26,77,1262]
nums3 = [1,19,29,33,67,88]
nums4 = [36,47,55,88,128,765]
data = [nums1, nums2, nums3, nums4]

def mergeKnums(nums):
    n = len(nums)
    
    return binarySelect(nums, 0, n-1)

def merge2nums(nums1, nums2):
    if not nums1: return nums2
    if not nums2: return nums1
    
    i, j = 0, 0
    result = []
    while i < len(nums1) and j < len(nums2):
        if nums1[i] < nums2[j]:
            result.append(nums1[i])
            i += 1
        else:
            result.append(nums2[j])
            j += 1
    return result

def binarySelect(nums, left, right):
    if left == right: return nums[left]
    mid = left + (right-left)//2
    print(left, mid, right)
    nums1, nums2 = binarySelect(nums, left, mid), binarySelect(nums, mid+1, right)
    return merge2nums(nums1, nums2)
    
merge2nums(nums1, nums2)
mergeKnums(data)

 

posted @ 2023-02-13 20:52  今夜无风  阅读(33)  评论(0编辑  收藏  举报