[LeetCode]1313. Decompress Run-Length Encoded List

We are given a list nums of integers representing a list compressed with run-length encoding.

Consider each adjacent pair of elements [a, b] = [nums[2*i], nums[2*i+1]] (with i >= 0).  For each such pair, there are a elements with value b in the decompressed list.

Return the decompressed list.

 

Example 1:

Input: nums = [1,2,3,4]
Output: [2,4,4,4]
Explanation: The first pair [1,2] means we have freq = 1 and val = 2 so we generate the array [2].
The second pair [3,4] means we have freq = 3 and val = 4 so we generate [4,4,4].
At the end the concatenation [2] + [4,4,4,4] is [2,4,4,4].
 

Constraints:

2 <= nums.length <= 100
nums.length % 2 == 0
1 <= nums[i] <= 100

来源:力扣(LeetCode)
链接:https://leetcode-cn.com/problems/decompress-run-length-encoded-list
著作权归领扣网络所有。商业转载请联系官方授权,非商业转载请注明出处。

 

python3:

1 class Solution:
2     def decompressRLElist(self, nums: List[int]) -> List[int]:
3         rst = []
4         for i in range(len(nums)):
5             if 0 == i % 2:
6                 tmp = nums[i]*[nums[i + 1]] 
7                 rst += tmp
8         return rst

 

posted @ 2020-02-11 16:06  界757  阅读(108)  评论(0编辑  收藏  举报