[LeetCode]1295. Find Numbers with Even Number of Digits

Given an array nums of integers, return how many of them contain an even number of digits.
 

Example 1:

Input: nums = [12,345,2,6,7896]
Output: 2
Explanation:
12 contains 2 digits (even number of digits). 
345 contains 3 digits (odd number of digits). 
2 contains 1 digit (odd number of digits). 
6 contains 1 digit (odd number of digits). 
7896 contains 4 digits (even number of digits). 
Therefore only 12 and 7896 contain an even number of digits.
Example 2:

Input: nums = [555,901,482,1771]
Output: 1
Explanation:
Only 1771 contains an even number of digits.
 

Constraints:

1 <= nums.length <= 500
1 <= nums[i] <= 10^5

来源：力扣（LeetCode）
链接：https://leetcode-cn.com/problems/find-numbers-with-even-number-of-digits
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python3:

class Solution:
    def findNumbers(self, nums: List[int]) -> int:
        rst = 0
        for num in nums:
            digits = 0
            while num >= 1:
                num /= 10
                digits += 1
            if 0 == digits % 2:
                rst += 1
        return rst